Answer:
Distance xy = 11.66 unit (Approx)
Step-by-step explanation:
Given:
x(-7,10)
y(3,4)
Find:
Distance xy
Computation:
Distance = √(x2-x1)²+(y2-y1)²
Distance xy = √(3+7)²+(4-10)²
Distance xy = √ 100 + 36
Distance xy = 11.66 unit (Approx)
The two inequalities formed will be:
One for ticket quantity:
x + y ≤ 600
One for funds generated via tickets:
5x + 7y ≥ 3500
Equating x to 330,
5(330) +7y ≥ 3500
y = 265
Checking if the other inequality holds true:
330 + 265 ≤ 600
595 ≤ 600
This inequality is still true so they can sell 265 tickets on the event day and cover their expenses.
use this method when you do? - 14a + 200b + 16h = 1712
Answer:
both kinds of tickets are $5 each
Step-by-step explanation:
Let s and c represent the dollar costs of a senior ticket and child ticket, respectively. The problem statement describes two relationships:
12s + 5c = 85 . . . . . revenue from the first day of sales
6s + 9c = 75 . . . . . . revenue from the second day of sales
Double the second equation and subtract the first to eliminate the s variable.
2(6s +9c) -(12s +5c) = 2(75) -(85)
13c = 65 . . . . . simplify
65/13 = c = 5 . . . . . divide by the coefficient of c
Substitute this value into either equation. Let's use the second one.
6s + 9·5 = 75
6s = 30 . . . . . . . subtract 45
30/6 = s = 5 . . . divide by the coefficient of s
The price of a senior ticket is $5; the price of a child ticket is $5.
Answer:
D
Step-by-step explanation:
Just did it
