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Oliga [24]
3 years ago
15

4. The length of a rectangle is eight more than

Mathematics
1 answer:
monitta3 years ago
4 0

Answer:

length = 104/3 ft

width = 40/3 ft

Step-by-step explanation:

<u>Variables:</u>

L = length

w = width

<u>Set up equations:</u>

  • L = 8 + 2w
  • 2L + 2w = 96

<u>Substitute L with the first bullet point equation:</u>

2L + 2w =  96

2(8 + 2w) + 2w = 96

16 + 4w + 2w = 96

16 + 6w = 96

6w = 80

w = 40/3 ft

<u>Find L now that you have the value of the width:</u>

L = 8 + 2w

L = 8 + 2(40/3)

L = 8 + 80/3

L = 104/3 ft

<u>Final Values:</u>

length = 104/3 ft

width = 40/3 ft

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Your answer was correct!

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Answer:

2

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4 years ago
12x+7&lt;−11 AND5x−8≥4012
Arte-miy333 [17]

Answer:

No solution

Step-by-step explanation:

Given: 12x+7 and  5x-8\geq 40

Solve both inequality separately.

12x+7              Subtraction property of inequality

12x

12x

x

x

and

5x-8\geq 40               Addition property of inequality

5x\geq 40+8

5x\geq 48

x\geq \dfrac{48}{5}

Hence, the solution of the compound inequality intersection of both solutions.

Please find attachment for number line solution.

No solution

8 0
3 years ago
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