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natta225 [31]
2 years ago
7

mf help please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Andrej [43]2 years ago
4 0

Answer:

Your answer is A.

Hope this helps!

Step-by-step explanation:

Line r's equation is

y = - 4/3x - 4

And Line s's equation is

y = 2/5x - 2

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HELP PLSS ANYONE? I'VE TO SUBMIT ASAP
Alenkinab [10]

x =14

Answer:

m\angle ABC =  51°

Step-by-step explanation:

11. By inscribed angle theorem:

83°=\frac{1}{2} \times (9x+40)°\\\\83°\times 2 = (9x+40)°\\166°= (9x+40)°\\166 = 9x + 40\\166 - 40 = 9x\\126 = 9x\\\\x = \frac{126}{9}\\\\\huge \red {\boxed {x = 14}}

12. Again by inscribed angle theorem:

(5x+11)°=\frac{1}{2} \times (16x-26)°\\\\2\times (5x+11)°= (16x-26)°\\(10x+22)°= (16x-26)°\\10x + 22 = 16x - 26\\22+26 = 16x - 10x\\48= 6x\\\\x = \frac{48}{6}\\\\\huge \purple{\boxed {x = 8}}\\m\angle ABC =  (5x+11)°\\m\angle ABC =  (5\times 8+11)°\\m\angle ABC =  (40+11)°\\\huge \orange{\boxed {m\angle ABC =  51°}} \\

7 0
3 years ago
The number of texts per day by students in a class is normally distributed with a 
kobusy [5.1K]

Answer:

1, 2, 6

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation

Given that mean (μ) = 130 texts, standard deviation (σ) = 20 texts

1) For x < 90:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{90-130}{20} =-2

From the normal distribution table, P(x < 90) = P(z < -2) = 0.0228 = 2.28%

Option 1 is correct

2) For x > 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

From the normal distribution table, P(x > 130) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 50%

Option 2 is correct

3) For x > 190:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{190-130}{20} =3

From the normal distribution table, P(x > 3) = P(z > 3) = 1 - P(z < 3) = 1 - 0.9987 = 0.0013 = 0.13%

Option 3 is incorrect

4)  For x < 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

For x > 100:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{100-130}{20} =-1.5

From the normal table, P(100 < x < 130) = P(-1.5 < z < 0) = P(z < 0) - P(z < 1.5) = 0.5 - 0.0668 = 0.9332 = 93.32%

Option 4 is incorrect

5)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

Option 5 is incorrect

6)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{160-130}{20} =1.5

Since 1.5 is between 1 and 2, option 6 is correct

5 0
2 years ago
Which of the following are the factors of 4b^2-16?
vladimir2022 [97]
The answer is B hope this helps

6 0
3 years ago
Read 2 more answers
Two separate bacteria populations grow each month and are represented by the
ASHA 777 [7]

Answer:

Option 4.) month 4

Step-by-step explanation:

we have

f(x)=3^{x} ----> equation A

g(x)=7x+6 ----> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

The solution is the point (3,27)

That means -----> For x=3 months, the populations in both functions are the same (the bacteria populations is 27)

therefore

For x> 3 months the f(x) population is greater then the g(x) population

5 0
2 years ago
How do I solve this literal equation? <br> 15 points
kati45 [8]

Answer:

\pi = \frac{A}{2r^2 + 2rh}

Step-by-step explanation:

First, we need to isolate \pi by taking it common from both terms on the right:

A=2\pi r^2 + 2\pi rh\\A=\pi (2r^2 + 2rh)

Now, since we want \pi in terms of the other variables, we can divide the left hand side (A) by whatever is multiplied with \pi on the right hand side. Then we will have an expression for \pi. Shown below:

A=\pi (2r^2 + 2rh)\\\pi = \frac{A}{2r^2 + 2rh}

This is the xpression for \pi

7 0
3 years ago
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