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3 years ago

Answer the question in the picture below

Mathematics

1 answer:

iren2701 [21]3 years ago

8 0

Answer:

16.25, 20, 13.75, 12.5, 7.5

Step-by-step explanation:

1cm= 2.5m

6.5x2.5= 16.25

8x2.5= 20

5.5x2.5= 13.75

5x2.5= 12.5

3x2.5= 7.5

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How can exponents help you find the area of a rectangle if each side length is multiplied by x?

NeX [460]

Exponents can make the problem smaller and look less confusing. If you see a problem with 5*5*5*5*5*5*5*5 then you're going to eventually loose count and will have to keep repeating. But if you put 5 to the 8th power then you know right away just to multiply 5, (8) times,

4 0

3 years ago

X = y = m ∠ H = m ∠ G =

Lorico [155]

Answer:

x=53

y=26

H=106

G=93

Step-by-step explanation:

By the inscribed quadrilateral conjecture:

$2x+(x+21)=180\\(3y+9)+(4y-11)=180\\3x+21=180\\3x=159\\x=53\\7y-2=180\\7y=182\\y=26\\H=2(53)=106\\G=(4(26)-11)=104-11=93$

Hope this helps!

4 0

3 years ago

Given: 1 and 2 are supplements, and 3 and 2 are supplements.

Ronch [10]

The correct answers are:

Supplementary; ∠2 and ∠3; substitution; 2.

Explanation:

Supplementary angles are angles whose measures sum to 180°. Thus this is the first answer.

Since we are told that ∠2 and ∠3 are supplementary, their measures sum to 180° and they are the second answer.

We know that m∠1 + m∠2 = 180° and m∠2 + m∠3 = 180°. We can substitute "m∠2 + m∠3" for 180° in the first equation; this is the substitution property.

To isolate m∠1 on the right, we will subtract m∠2 from each side, and get that m∠1 = m∠3 and the angles are congruent.

5 0

3 years ago

Read 2 more answers

2 Points What is the slope of the line shown below? (2,2) 4,8

Vladimir79 [104]

Answer:

Step-by-step explanation:

Slope =y2−y1 divided to x2−x1

8−2

4−2

6/2

= 3

Hope this helped :)

Have a good one

5 0

3 years ago

Read 2 more answers

Prove this trigonometric equation; - tan^2x + sec^2x = 1,

alekssr [168]

Hey there :)

- tan²x + sec²x = 1 or 1 + tan²x = sec²x

sin²x + cos²x = 1
Divide the whole by cos²x

$\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}$

$\frac{sinx}{cosx} = tanx$ so $\frac{sin^2x}{cos^2x} = tan^2x$
and
$\frac{1}{cosx} = secx$ so $\frac{1}{cos^2x} = sec^2x$

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}

1 = - tan²x = sec²x or sec²x - tanx = 1

3 0

3 years ago