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il63 [147K]
2 years ago
10

Is this a function or not a function?

Mathematics
1 answer:
zhuklara [117]2 years ago
6 0

Answer:

This is indeed a function

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Exhibit 12-4 In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Li
snow_lady [41]

Answer:

b. multinomial population

Step-by-step explanation:

The data is categorical and non-overlapping. That is, there are multiple options(either the student is in the Liberal Arts College, Business College or Education College), and he cannot be in more than one option.

So this is an example of a multinomial population.

The correct answer is:

b. multinomial population

7 0
3 years ago
Malia buys 2 loaves of bread priced at $2.46 per loaf and 2 pound of cheese priced at
aleksandrvk [35]
She spent $19.88 on cheese and bread
7 0
2 years ago
I need help plz help me
Tresset [83]

Answer:

26

Step-by-step explanation:

Because DAC is a straight line we can equate that:

4x - 8 + 34 + 76 - x = 180

3x + 102 = 180

3x = 78

x = 26

5 0
3 years ago
Read 2 more answers
A pair of equations is shown below:
Elan Coil [88]
So, both equations are essentially linear equations.
Linear equations are written in the format y = mx+b, where m represents the slope/slope intercept and b represents the y-intercept.
---------------------------------------------------------------------------------------------------------------
Part A
the slope and y-intercept

y = mx +b
m - the slope; b- y-intercept

therefore;

y = 6x - 4
m = 6; b = -4

y = 5x - 3
m = 5; b = -3

The coordinates of the point where the lines are crossed are the solution to the system of linear equations.

How to graph the lines:
y = 6x - 4
y-intercept (0; -4)
for x = 1 ⇒ y = 6 · 1 - 4 = 6 - 4 = 2 ⇒ (1; 2)

y = 5x - 3
y-intercept (0; -3)
for x=1 ⇒ y = 5 · 1 - 3 = 5 - 3 = 2 ⇒ (1; 2)

***look at the img for graph reference***

Part B: x = 1; y = 2

4 0
3 years ago
Excuse my doodle! please help!
vlabodo [156]

Answer:

f‐¹(x) = 4x² - 3, for x < 0.

Nice doodle :P

7 0
2 years ago
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