Amount of dog treat that Dieon has = 3/4 pound
Amount of dog treat that Dieon gives his dog each day = 1/8
Let us assume the number of days the dog treat will last = x
Then
(1/8) * x = (3/4)
x/8 = 3/4
x = (3 * 8)/4
= 3 * 2
= 6
So we can see from the above deduction that the dog treat will last for 6 days. I hope the procedure is clear enough for you to understand.
The top right is the answer. The base should be square with lengths of 8 and the height is 10.
Answer: The correct answer is option C: Both events are equally likely to occur
Step-by-step explanation: For the first experiment, Corrine has a six-sided die, which means there is a total of six possible outcomes altogether. In her experiment, Corrine rolls a number greater than three. The number of events that satisfies this condition in her experiment are the numbers four, five and six (that is, 3 events). Hence the probability can be calculated as follows;
P(>3) = Number of required outcomes/Number of possible outcomes
P(>3) = 3/6
P(>3) = 1/2 or 0.5
Therefore the probability of rolling a number greater than three is 0.5 or 50%.
For the second experiment, Pablo notes heads on the first flip of a coin and then tails on the second flip. for a coin there are two outcomes in total, so the probability of the coin landing on a head is equal to the probability of the coin landing on a tail. Hence the probability can be calculated as follows;
P(Head) = Number of required outcomes/Number of all possible outcomes
P(Head) = 1/2
P(Head) = 0.5
Therefore the probability of landing on a head is 0.5 or 50%. (Note that the probability of landing on a tail is equally 0.5 or 50%)
From these results we can conclude that in both experiments , both events are equally likely to occur.
Answer:
x = 1
Step-by-step explanation:
plug y = 6 on to the equation y =x + 5
=> 6 = x +5
=> x = 1
Xy=12
xdy/dx + y = 12
xdy/dx = 12 - y
dy/dx= (12-y) /x
dy/dx | x=-4 ,y=-3 = (12-(-3))/(-4)
= (12+3)/-4 = -15/4
