Answer:

149 engines in 9th year
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
Please have a look at the attached photo.
My answer:
From a look at the photo and the data plot can be represented by the function, so we can pick 2 points in our given graph
- (x1, y1) = (2,60)
- (x2, y2) = (5,99)
The standard form of a linear equation is:
y = mx + b where:
- m is the slope
- b is the y-intercept
We know the slope of the function can be found as following:
so in this situation we have:
<=> 
=> y = 13x + b (1)
Because the line goes through point (2,60) so we substitute it into (1):
60 = 13*2 + b
<=> b = 60 - 26 = 34
=> y = 13x + 34
Now we will substitute x=9 to find the engines produced by company in 9th year as:

Hence, the company will produce 149 engines in 9th year
Answer:
11.8294Step-by-step explanation:
Answer:
1. 14
2. 20
3. 12
4. -400
5. 6
6. 21
7. 11
8. 16
9. 40
10. 49
11. 12
12. IDK
Step-by-step explanation:
1. 16-2=14
2. 16+4=20
3. 6 X 2 = 12
4. -400/-10 (negative divided by a negative equals a positive) = 40
5. 6 X 6 = 36
6. 16+5=21
7. 23-12=11
8. 4 X 16 = 64
9. 36-16=20, 20 X 2 = 40
10. 400-8=392, 392/8= 49
11. 912-612=300, 300/25 = 12
12. Sorry too confusing.
It does not say simple or compound interest.
Simple interest is rarely used these days, so assume compound.
Use the standard formula:
future value = present value*(1+rate/n)^(nt)
n=number of times interest is compounded per year (=1)
t=number of years
Plugging values,
200=100(1.09)^t
1.09^t = 2
take log
t(log(1.09))=log 2
t=log(2)/log(1.09)=0.6931/0.08618=8.04 years.