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The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.
Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.
By the fundamental theorem of calculus,
The definite integral corresponds to the area of a trapezoid with height 2 and "bases" of length 5 and 2, so
There’s probably an easier way to do it like with the equation to find the area of a trapezoid but i did it this way bc it’s easier for me
i split the trapezoid into a triangle and a square
with the pythagorean theorem i found the missing side length to find the area of the square (length X width)
then found the area of the triangle (base X height divided by 2)
THE ANSWER IS 68.9 CM
i split the trapezoid into a triangle and a square
with the pythagorean theorem i found the missing side length to find the area of the square (length X width)
then found the area of the triangle (base X height divided by 2)
THE ANSWER IS 68.9 CM