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Reika [66]
2 years ago
12

how many numbers did bill wrote if he wrote all the natural numbers between w and v not including w and v

Mathematics
1 answer:
dexar [7]2 years ago
4 0

Answer:

v - w - 1

Step-by-step explanation:

Try an experiment with a small, specific set of numbers like:

4, 5, 6, 7, 8, 9, 10   w = 4 and v = 10.

There are 5 numbers in the list, not counting the first and last.  Is this related to the difference between v and w?  v - w = 6, one more than 5.

The number of natural numbers between  w  and  v, not including  w  and  v, is v - w - 1.

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I will say its the correct answer
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Set up a proportion and solve the height of the three .
Naddik [55]

Answer:

60 feet

Step-by-step explanation:

Setting the proportion up:

x/25=24/10

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Read 2 more answers
Carlos has at most $40 to spend on food for a barbeque. He wants to buy hot dogs and hamburgers and then
poizon [28]

Answer:

$8.50

Step-by-step explanation:

I don't know what Alls are, but if Carlos insists, we can calculate how much he can spend on Alls with the expression:

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3 0
1 year ago
The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep
Alchen [17]
Ooh, fun

geometric sequences can be represented as
a_n=a(r)^{n-1}
so the first 3 terms are
a_1=a
a_2=a(r)
a_2=a(r)^2

the sum is -7/10
\frac{-7}{10}=a+ar+ar^2
and their product is -1/125
\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3

from the 2nd equation we can take the cube root of both sides to get
\frac{-1}{5}=ar
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r
subsituting -1/5 for ar
\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r
which simplifies to
\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for ax^2+bx+c=0
x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}
so
for 2r²-5r+2=0
a=2
b=-5
c=2

r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}
r=\frac{5 \pm \sqrt{25-16}}{4}
r=\frac{5 \pm \sqrt{9}}{4}
r=\frac{5 \pm 3}{4}
so
r=\frac{5+3}{4}=\frac{8}{4}=2 or r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}

use them to solve for the value of a
\frac{-1}{5}=ar
\frac{-1}{5r}=a
try for r=2 and 1/2
a=\frac{-1}{10} or a=\frac{-2}{5}


test each
for a=-1/10 and r=2
a+ar+ar²=\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}
it works

for a=-2/5 and r=1/2
a+ar+ar²=\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}
it works


both have the same terms but one is simplified

the 3 numbers are \frac{-2}{5}, \frac{-1}{5}, and \frac{-1}{10}
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3 years ago
How Can I Use Decimal Grids to model Tenths?
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