First, the need to determine if the statements are true or false.
1) January is the first month of the year. (This statement is true)
2) December is the last month of the year. (This statement is also true)
With this in mind we can determine that what will illustrate the truth value would be:
T T -> T
In other words, since the first statement is true and the second statement is also true then conjunction of both statements would be true.
B is a times b
C is also a times b
sorry im stuck on the rest
Answer:
The number of observations is 15.
Answer:
y=27
Step-by-step explanation:
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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