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Vitek1552 [10]
3 years ago
7

Laura has invited 48 guests to her company's Christmas party this year. If she expects each person to drink 3 cups of eggnog, th

en how many gallons does she need to buy?
Mathematics
2 answers:
oksian1 [2.3K]3 years ago
7 0
The answer would be 9 gallon because you would multiply 48 and 3 the divide the answer (144) by 16 (how many cups in one gallon and get you answer, 9. hope this helps :)
LuckyWell [14K]3 years ago
5 0
I would say 9. I may have calculated this wrong but she expects each guest to drink 3 cups so 48x3= 144 cups. There are 16 cups to a gallon. 144cups/ 16cups= 9 gallons
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A dog breeder would like to know how many Dalmatian puppies are typically born in a litter. He conducts some research and select
podryga [215]

Answer:

c. 6.2 ± 2.626(0.21)

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 101 - 1 = 100

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.626

The confidence interval is:

\overline{x} \pm M

In which \overline{x} is the sample mean while M is the margin of error.

The distribution of the number of puppies born per litter was skewed left with a mean of 6.2 puppies born per litter.

This means that \overline{x} = 6.2

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.626\frac{2.1}{\sqrt{101}} = 2.626(0.21)

In which s is the standard deviation of the sample and n is the size of the sample.

Thus, the confidence interval is:

\overline{x} \pm M = 6.2 \pm 2.626(0.21)

And the correct answer is given by option c.

5 0
3 years ago
The sum of three consecutive terms of an arithmetic sequence is 27, and the sum of their squares is 293. What is the absolute di
Ber [7]

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d = common difference

let

a = centre term

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a - d,  a, a + d

a - d +  a + a + d = 27

3a = 27

a = 27 / 3

a = 9

Therefore,

(a-d)² + (a)² + (a + d)² = 293

(a²-2ad+d²) + 9² + (a² + 2ad + d²) = 293

(81 - 18d + d²) + 81 + (81 + 18d + d²) = 293

243 + 2d² = 293

2d² = 50

d² = 50 / 2

d = √25

d = 5

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Therefore, the 3 numbers are as follows

9 - 5 , 9, 9 + 5 = 4, 9, 14

The difference between the greatest and the least of these 3 numbers are as follows:

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learn more on Arithmetic progression: brainly.com/question/25749583?referrer=searchResults

7 0
2 years ago
Help ? Plz forgot the steps (3z+9)(z-4)
Dafna11 [192]
It's a binomial times a binomial, so you FOIL
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Then multiply Outers:
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Then, throw it all together in descending order, starting with the variable of highest degree to lowest:
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Last of all, simplify coefficients with like terms and you're good to go:
3z^2 - 3z - 36
Hope this helps!
3 0
3 years ago
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