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3 years ago

Nvm I dont need help thank you

Mathematics

2 answers:

olganol [36]3 years ago

5 0

Answer:

I'm glad that I helped you out

Lelechka [254]3 years ago

4 0

I am glad you found it out all my your self

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Please explain how they plugged the removable discontinuity in this question.

kondor19780726 [428]

In the limit

$\displaystyle \lim_{x\to c} f(x)$

we're interested in the value that $f(x)$ converges to as $x$ gets closer to $c$ . So in fact $x\neq c$ .

In the given example, $f(x)$ is factorized to reveal a common factor of $x-1$ in the numerator and denominator. We have $x\neq1$ if $x\to1$ , so $x-1\neq0$ so we can simplify

$\dfrac{x-1}{x-1} = 1$

and *remove* the discontinuity.

Then

$\displaystyle \lim_{x\to1} \frac{2(x-1)}{(x+1)(x-1)} = \lim_{x\to1} \frac2{x+1} = \frac2{1+1} = 1$

8 0

2 years ago

Lemur [1.5K]

Answer:

x + 6

Step-by-step explanation:

consider the x- coordinates of the right angle

x- coordinate of A = - 4

x- coordinate of B = 2

then

| 2 - (- 4) | = | 2 + 4 | = | 6 | = 6

the x- coordinate has been shifted 6 units to the right , so the rule is

x + 6

5 0

2 years ago

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

7 0

4 years ago

Which table of ordered pairs represents a function?

liraira [26]

Your answer is the top left

5 0

3 years ago

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leslie decides to join a gym she must pay a monthly fee plus a one time free to open a membership the sititution can be modeled

Feliz [49]

55 is the monthly fee
x is for every month she has to pay
80 is the one time fee

6 0

3 years ago

Read 2 more answers