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2 years ago

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Last year there were 30 students in the Chess Club. If the number of students in the Rubik's Cube Club was 20% greater than the

number of students in the Chess Club, how many students were in the Rubik's Cube Club?
A. 30
B. 42
C. 36
D. 58

1 answer:

Nimfa-mama [501]2 years ago

3 0

C.36
you would multiply 30 times 20, then divide that total by 100 which will give you 6 then add the 6 to the 30 and get 36.

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A circle is defined by the equation x2 + y2 + 8x + 22y + 37 = 0. What are the coordinates for the center of the circle and the l

inn [45]

We can say that:
8x = -2ax
8 = -2a
a = -4

22y = - 2by
22 = -2b
b = -11

37 = a² + b² - r²
37 = (-4)² + (-11)² - r²
r² = 16 + 121 - 37
r² = 100
r = 10

With all this information, we can say that:
The center of the circle is: (-4 ; -11)
and the radius of the circle is r = 10

P.S:
(a - x)² + (b-y)² = r²
a² - 2ax + x² + b² -2by + y² - r² = 0
x² + y² -2ax - 2by + a² + b² - r² = 0

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3 years ago

Can Someone Help Please.

djverab [1.8K]

Answer:

1. y = 9280 - 20x

2. f(y) = 6.37y - 3

Step-by-step explanation:

1. The equation is given to be $\frac{1}{16}x + \frac{1}{320}y - 29 = 0$

Now, rearranging the function we can write

$\frac{y}{320} = 29 - \frac{x}{16}$

⇒ y = 9280 - 20x

Hence, this is the equation as a function of x. (Answer)

2. The given function is y - 6.37x = - 3

Therefore, we can write, y = 6.37x - 3

Hence, f(x) = 6.37x - 3

⇒ f(y) = 6.37y - 3.

Hence, option D is true. (Answer)

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2 years ago

3 + b/9 < 4<br>show work please

Gekata [30.6K]

First, before multiplying to cancel the fraction, let's isolate x by subtracting both sides by 3:

b/9 < 1

To cancel out the fraction, we multiply both sides by 9:

x < 9

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3 years ago

HELP!!!!!!!!!!!!!!! 15 POINTS

disa [49]

$60 for 2 hours and $100 in total for 2 hours of work and the service fee

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2 years ago

Domain and range of the inequality y<√x+3 +1

Margaret [11]

The domain of the given inequality is y>1.

<h3>What is Inequality?</h3>

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.

Here, given inequality:

y < $\sqrt{x+3}+1$

Related equation:

y = $\sqrt{x+3}+1$

The equation defined as,

x+3 > 0

x > -3

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

$\sqrt{x+3} \geq 0$

adding 1 on both sides, we get

$\sqrt{x+3} + 1 \geq 1$

y ≥ 1

The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.

Thus, the domain of the given inequality is y>1.

Learn more about Inequality from:

brainly.com/question/20383699

#SPJ1

6 0

1 year ago