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3 years ago

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Last year there were 30 students in the Chess Club. If the number of students in the Rubik's Cube Club was 20% greater than the

number of students in the Chess Club, how many students were in the Rubik's Cube Club?
A. 30
B. 42
C. 36
D. 58

1 answer:

Nimfa-mama [501]3 years ago

3 0

C.36
you would multiply 30 times 20, then divide that total by 100 which will give you 6 then add the 6 to the 30 and get 36.

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Step-by-step explanation:

Do the calculation.

5- 13= -8

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My problem is : P=2L+2W solve for L

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Answer:
L = P/2 - W

Explanation:
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Chance can wash the car in 2 hours, while Sandy can wash the same car in 4 hours. How many hours would it take for them to wash

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Step-by-step explanation:

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DerKrebs [107]

Answer:

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 48564, \sigma = 3293, n = 281, s = \frac{3293}{\sqrt{281}} = 196.44$

What is the probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct?

This is the pvalue of Z when X = 48101. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{48101 - 48564}{196.44}$

$Z = -2.36$

$Z = -2.36$ has a pvalue of 0.0091

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

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