All categories

3 years ago

Sam had 1 1/2 m of rope. he cut 5/8 m used it for a project. how much rope does sam have left

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

8 0

You have to subtract 5/8 from 11/2. then you will get the answer if you put it in a calculator.

You might be interested in

Sove the equation and verify

Nostrana [21]

Let's break the equation in several step to make things more clear: first of all, the numerator of the left hand side simplifies to

$\dfrac{2x}{3}-\dfrac{1}{2} = \dfrac{4x-3}{6}$

Similarly, the denominator becomes

$\dfrac{3x}{4}-\dfrac{1}{2} = \dfrac{3x-2}{4}$

Dividing by a fraction means to multiply by the inverse of that fraction:

$\dfrac{\frac{a}{b}}{\frac{c}{d}} = \dfrac{a}{b}\cdot\dfrac{d}{c}$

So, in your case, we have

$\dfrac{\frac{2x}{3}-\frac{1}{2}}{\frac{3x}{4}-\frac{1}{2}} = \dfrac{\frac{4x-3}{6}}{\frac{3x-2}{4}} = \dfrac{4x-3}{6}\cdot \dfrac{4}{3x-2} = \dfrac{2(4x-3)}{3(3x-2)} = \dfrac{8x-6}{9x-6}$

So, the equation has become

$\dfrac{8x-6}{9x-6} = \dfrac{4}{3}$

Multiply both sides by 3(9x-6):

$3(8x-6) = 4(9x-6) \iff 24x-18 = 36x-24$

Subtract 24x from both sides, and add 18 to both sides:

$36x-24x = 24-18 \iff 12x=6 \iff x = \dfrac{1}{2}$

8 0

3 years ago

Please help me if you know!! Thank you so much!!

Rus_ich [418]

Answer:

The Chinese act

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

You run 1 3/4 miles each day. Your friend runs 4times as far as you do. How far does your friend run each day

Inga [223]

Just make 1 3/4 an improper fraction and multiply by 4:

1 3/4 = 7/4

7/4 * 4 = 7

7 0

3 years ago

Read 2 more answers

At the frozen yogurt shop, a machine fills cups with 4 ounces of frozen yogurt before adding the toppings. After the cups are fi

Otrada [13]

What are the options?

3 0

3 years ago

Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)

USPshnik [31]

See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
$M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) + f(\frac{x_{1} + x_{2} }{2}) + ... + f(\frac{x_{n-1} + x_{n} }{2})]$

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
$M_{4} = \frac{1 - 0}{4} [ f(\frac{0 + \frac{1}{4} }{2}) + f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) + f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]$
$M_{4} = \frac{1}{4} [ f(\frac{1}{8}) + f(\frac{3}{8}) + f(\frac{5}{8}) + f(\frac{7}{8})]$

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
$M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]$

$M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]$

M₄ = 1/4 · (2 - 478/512)
= 0.2666

Hence, the <span>area of the region bounded by y = x³ and y = x</span> is approximately 0.267 square units.

6 0

3 years ago