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frutty [35]
3 years ago
11

Tramain made the table below for the system of equations y=2x+1 and y=-3x+11

Mathematics
1 answer:
frosja888 [35]3 years ago
5 0
Boy that math stuff will kill a cracker
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Y varies directly as x . when x=3 , then y=12 . find y when x=20.
Phoenix [80]

Answer:

Congress. would equal 80 due to x being worth 1/4 of y's total.

3 0
2 years ago
What are correct statements about the function f(x) = (x+3)(2x-4)(x+3)(2x-1)
labwork [276]
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8 0
3 years ago
Twice the sum of x and y decreased by 21
Semenov [28]
Answer: 2((x+y)-21)

Calculation/Explanation:

Twice the sum of x and y decreased by 21 means that you must add x and y first before decreasing by 21. The last step is to double the whole equation that we just performed.
8 0
3 years ago
Use the following problem to answer the question below: Given: 3(x – 4) = 33 Prove: x = 15 Statements Reasons 3(x – 4) = 33 Give
lawyer [7]

Answer:

Inverse Property of Addition (Reason C)

Step-by-step explanation:

<u>Given:</u> 3(x – 4) = 33

<u>Prove: </u>x = 15

Statements                                    Reasons

1. 3(x – 4) = 33                                  Given

2. 3x – 12 = 33                         Distributive Property (Reason A)

3. 3x – 12 + 12 = 33 + 12         Addition Property of Equality (Reason B)

4. 3x + 0 = 45                          Inverse Property of Addition (Reason C)

5.  3x = 45                               Zero Addition Property (Reason D)

6.  x = 15                                  Division Property of Equality

8 0
4 years ago
How do I solve part A
seraphim [82]

Answer:

The solution of this expression is x_{1} = -1 and x_{2} = -\frac{1}{2}.

Step-by-step explanation:

The procedure for solution of exercise A is described below:

1) We expand the expression.

2) The resulting expression is rearranged into the form of a second order polynomial.

3) Roots are found by Quadratic Formula.

Step 1:

2\cdot x \cdot (x+1.5) = -1

2\cdot (x^{2}+1.5\cdot x) = -1

2\cdot x^{2} + 3\cdot x = -1

Step 2:

2\cdot x^{2}+3\cdot x +1 = 0

Step 3:

x_{1, 2} = \frac{-3\pm \sqrt{3^{2}-4\cdot (2)\cdot (1)}}{2\cdot (2)}

x_{1,2} = -\frac{3}{4}\pm \frac{1}{4}

x_{1,2} = \frac{-3\pm 1}{4}

The solution of this expression is x_{1} = -1 and x_{2} = -\frac{1}{2}.

4 0
3 years ago
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