1.) Factor 9u^2-12u
2.) Cancel any common factors (in bold will be the terms eliminated)
Final answer is:
3u-4
Therefore, the answer is
C. 3u-4
Answer:
terminating
Step-by-step explanation:
if the given fraction is terminating then prime factors of denominator should be 2^n x 5^m where m and n are whole number
5=1x5=2^0x5^1
so it is of form 2^nx5^m
Answer:
112
Step-by-step explanation:
Just solve it easy peasy
![7[(25+9)-3(2-1)]](https://tex.z-dn.net/?f=7%5B%2825%2B9%29-3%282-1%29%5D)
First solve the inner brackets
![7[(34)-3(3)]\\7[25-9]](https://tex.z-dn.net/?f=7%5B%2834%29-3%283%29%5D%5C%5C7%5B25-9%5D)
Now the other brackets
![7[25-9]\\7[16]\\112](https://tex.z-dn.net/?f=7%5B25-9%5D%5C%5C7%5B16%5D%5C%5C112)
Answer:
x = 50*e∧ -t/100
Step-by-step explanation:
We assume:
1.-That the volume of mixing is always constant 300 gallons
2.-The mixing is instantaneous
Δ(x)t = Amount in - Amount out
Amount = rate * concentration*Δt
Amount in = 3 gallons/ min * 0 = 0
Amount out = 3 gallons/min * x/ 300*Δt
Then
Δ(x)t/Δt = - 3*x/300 Δt⇒0 lim Δ(x)t/Δt = dx/dt
dx/dt = - x/100
dx/ x = - dt/100
A linear first degree differential equation
∫ dx/x = ∫ - dt/100
Ln x = - t/100 + C
initial conditions to determine C
t= 0 x = 50 pounds
Ln (50) = 0/100 * C
C = ln (50)
Then final solution is:
Ln x = - t/100 + Ln(50) or
e∧ Lnx = e ∧ ( -t/100 + Ln(50))
x = e∧ ( -t/100) * e∧Ln(50)
x = e∧ ( -t/100) * 50
x = 50*e∧ -t/100
Answer:
C and D
Step-by-step explanation:
A number used to multiply a variable. Example: 6z means 6 times z, and "z" is a variable, so 6 is a coefficient.
