Answer:
9/10
Step-by-step explanation:
Answer:
x= 37.5°
Step-by-step explanation:
∠CBD
= 180° -75° (adj. ∠s on a str. line)
= 105°
∠BCD= ∠BDC (base ∠s of isos. △BCD)
∠BCD= x
∠BCD +∠BDC +∠CBD= 180° (∠ sum of △BCD)
x +x +105°= 180°
2x= 180° -105°
2x= 75°
x= 37.5°
<u>Alternative</u><u> </u><u>working</u><u>:</u>
∠BDA= (180° -75°) ÷2 (base ∠s of isos. △ABD)
∠BDA= 52.5°
∠BDA +∠BDC= 90°
52.5° +x= 90°
x= 90° -52.5°
x= 37.5°
I think the answer is (-2-\sqrt(10))/(3)
i know that looks wierd...sorry...i hope this helps
This would be displayed as
3x/5
Answer: The top of the Crane is 31 feet above the ground.
Step-by-step explanation:
When it is fully extended, the crane arm forms a 30 degree angle with a line parallel to the ground. This means that a right angle triangle is formed. The length of the Crane's arm represents the hypotenuse. The horizontal distance represents the adjacent side of the right angle triangle. The distance, h of the top of the Crane from the ground represents the opposite side of the right angle triangle.
To determine h, we would apply
the Sine trigonometric ratio.
Sin θ, = opposite side/hypotenuse. Therefore,
Sin 30 = h/62
h = 62Sin30
h = 62 × 0.5
h = 31 feet
