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2 years ago

Please help meeeeeeeee!!!!!!!!

Mathematics

2 answers:

icang [17]2 years ago

5 0

Answer:

MAG ANSWER KA MAG ISA!!!!!!

MArishka [77]2 years ago

3 0

Wing stop ————————————————-

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What’s is the answer

Natasha_Volkova [10]

Answer:

In simplest form, it should be:

3:2

6 / 2 = 3

4 / 2 = 2

Hope this helps!

8 0

2 years ago

In a equation below, for what value of c does x=4? 1/2(2x+4)=3x-c

oksano4ka [1.4K]

Answer:

c = 6

Step-by-step explanation:

1/2 (2(4) + 4) = 3(4) - c

1/2 (8 + 4) = 12 - c

1/2 (12) = 12 - c

6 = 12 - c

-6 = -c

c = 6

5 0

2 years ago

A triangle has two sides of length 13 and 10. What is the largest possible whole-number length for the third side?

NeTakaya

In order for a triangle to exist, the two smaller sides must add to a number greater than the largest side.

So, 13+10 = 23

So, the number has to be smaller than 23, and the largest whole number less than 23 is 22.

22 Is the largest possible whole number.

8 0

3 years ago

Plz help me thank you so much

BartSMP [9]

Answer:

7. b

8. a

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Determine the equation of the circle graphed below. ( please help me )

Brums [2.3K]

Answer:

$Equation : \\(x+3)^2 + ( y -2)^2 = 36$

Step-by-step explanation:

For standard form the circle's equation we need the centre of the circle and the radius.

Step 1: Find the centre

If the centre is not given find the end points of the diameter

and then find the mid point.

Let the end points of the diameter be : ( - 3 , 8 ) and ( -3 , -4 )

The mid-point of the diameter is :

$Mid-point = (\frac{-3 + - 3}{2}, \frac{-4+8}{2}) = (-3, 2)$

Therefore, centre of the circle = ( -3 , 2 )

Step 2 : Find radius

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the end points ( -3 , 8) and ( -3 , -4 )

That is ,

$Diameter = \sqrt{(-3-(-3))^2 + ( -4 -8)^2}\\$

$= \sqrt{(-3 + 3)^2 + (-12)^2}\\\\=\sqrt{0 + 144}\\\\=12$

Therefore ,

$Radius = \frac{12}{2} = 6$

Step 3 : Equation of the circle

Standard equation of the circle with centre ( h ,k )

and radius ,r is :

$(x - h)^2+(y -k)^2 = r^2$

Therefore, the equation of the circle with centre ( -3, 2)

and radius = 6 is :

$(x - (-3))^2 + (y - 2)^2 = 6^2\\\\(x + 3)^2 + (y - 2)^2 = 36$

5 0

2 years ago

Please help meeeeeeeee!!!!!!!!​

Please help meeeeeeeee!!!!!!!!