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kondor19780726 [428]
3 years ago
9

PLEASE HELP!

Mathematics
1 answer:
tresset_1 [31]3 years ago
8 0

Answer:

Only A is not Pythagorean Identity.

Step-by-step explanation:

Let us draw a unit circle as shown in the attached figure.

In the given figure, let us apply Pythagorean theorem, which is given by

x^2+y^2=z^2\\\\x=\sin\theta,y=\cos\theta,z=1\\\\\sin^2\theta+\cos^2\theta=1^2\\\\\sin^2\theta+\cos^2\theta=1........(C)

Divide both sides by \sin^2\theta

\frac{\sin^2\theta}{\sin^2\theta}+\frac{\cos^2\theta}{\sin^2\theta}=\frac{1}{\sin^2\theta}\\\\1+\cot^2\theta=\csc^2\theta.......(B)

Divide both side of identity C by  \sin^2\theta

\frac{\sin^2\theta}{\cos^2\theta}+\frac{\cos^2\theta}{\cos^2\theta}=\frac{1}{\cos^2\theta}\\\\\tan^2\theta+1=\sec^2\theta.......(D)

Therefore, only A is not Pythagorean Identity.

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Step-by-step explanation:

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