Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).
Let <em>x</em> be the inverse. Then <em>x</em> is such that
23<em>x</em> ≡ 1 (mod 1000)
Use the Euclidean algorithm to solve for <em>x</em> :
1000 = 43×23 + 11
23 = 2×11 + 1
→ 1 ≡ 23 - 2×11 (mod 1000)
→ 1 ≡ 23 - 2×(1000 - 43×23) (mod 1000)
→ 1 ≡ 23 - 2×1000 + 86×23 (mod 1000)
→ 1 ≡ 87×23 - 2×1000 ≡ 87×23 (mod 1000)
→ 23⁻¹ ≡ 87 (mod 1000)
Answer:
Area = 250
Step-by-step explanation:
25 x 10
Length * Width
Answer:
Graph is attached :)
Step-by-step explanation:
Hope that helps!
Answer:
#1 : x= -16.5
#2 : x= 3.6
#3 : x= -75
#4 : x= 10 1/3
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Hope it helps :)
Please mark me brainlist!
