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1 year ago

Pls help WILL MARK BRAINLY also 34 POINTS

Mathematics

2 answers:

IRINA_888 [86]1 year ago

5 0

Answer:

The answer is 27 degrees for x, and 38 degrees for y.

Step-by-step explanation:

There are many ways you could do this. The easiest one for me was if you look at the left side of the 180 degree line (CD), you take away 90 (straight angle) from 63, which equals 27 degrees (answer for x). Then, add up all the angles on the left side of the 180 degree line. However, you need to first work out a, which is 180-128=52 degrees. Now you can add them up. 52 degrees (a) plus 27 (m) plus 63 (n) = 142 degrees. Then take away 180 from 142, which equals 39 degrees for y. If you want to check this Add up all your known angle on the left side of the 180 degree line. 52 plus 27 plus 63 plus 38, which equals 180 degrees, which is correct.

Licemer1 [7]1 year ago

4 0

Answer:

X is 38, y is 27.

Step-by-step explanation:

This is because you are subtracting on the 90 degree angles.

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WILL GIVE BRAINLIST PLS HELP Find x. Round your answer to the nearest tenth.

Llana [10]

Answer:

9. x=13.5

10. x=11.5

Step-by-step explanation:

6 0

2 years ago

The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds. the prob

Anni [7]

Given:
μ = 200 lb, the mean
σ = 25, the standard deviation

For the random variable x = 250 lb, the z-score is
z = (x-μ)/σ =(250 - 200)/25 = 2

From standard tables for the normal distribution, obtain
P(x < 250) = 0.977

Answer: 0.977

7 0

3 years ago

Can help me complete this problem please :c

motikmotik

Answer:

$A = \dfrac{7}{2}\pi~cm^2$

Step-by-step explanation:

There is a formula for the area of a sector given the radius and the angle measure.

$A = \dfrac{n}{360^\circ}\pi r$

n = angle measure

r = radius

$A = \dfrac{140^\circ}{360^\circ}\pi \times (3~cm)^2$

$A = \dfrac{14}{36}\pi \times 9~cm^2$

$A = \dfrac{7}{18}\pi \times 9~cm^2$

$A = \dfrac{7}{2}\pi~cm^2$

3 0

2 years ago

Read 2 more answers

At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

8 0

2 years ago

Remy drinks 214 cups of water every 145 hours.

Tcecarenko [31]

Answer:

1 69/145 cups

Step-by-step explanation:

We can use ratio's to solve this problem. We will put water over time

214 cups x cups

--------------- = --------------

145 hours 1 hours

Using cross products

214 *1 =145 x

Divide both sides by 125

214/145 = 145x/145

214/145 = x

145 goes into 215 1 time with 69 left over

1 69/145

4 0

2 years ago

Read 2 more answers