Answer:
The domain of (f*g) (x) is the set of all real numbers; ( -∞, ∞)
Step-by-step explanation:
(f*g) (x) simply means we obtain the product of f(x) and g(x). We are given that;
f(x)=2x
g(x)= 1/x
(f*g) (x) = f(x) * g(x)
(f*g) (x) = 2x * 1/x = 2
This is a horizontal line defined everywhere on the real line. The domain of (f*g) (x) is thus ( -∞, ∞)
Step-by-step explanation:
To solve, we have to remember PEMDAS (Parenthesis, Exponent, Multiply / Divide, Add or Subtract).
Here, the curly brackets act as parenthesis, so we solve that first.
• 3 + 7 = 10
Then, we multiply by 4.
• 10 • 4 = 40
Finally, we add 6 to 40.
• 40 + 6 = 46.
Our final answer: 46
Answer: Good luck buddy
Step-by-step explanation:
Answer:
The period of given function is 
So, Option B is correct.
Step-by-step explanation:
In this question we need to find the period of the function y= 3 sin x/8
The formula used to find period of function is: 
We need to know the value of b.
To find the value of b we compare the standard equation with the equation of function given.
Standard Equation: y = a sin(bx - c) +d
Given Equation: y= 3 sin(x/8)
Comparing we get:
a= 3
b= 1/8
c= 0
d=0
So, we get the value of b i.e 1/8. Putting it in the formula to find period of given function.
Solving,
So, the period of given function is
Answer: 4.5 miles
Explanation:
When you draw the situation you find two triangles.
1) Triangle to the east of the helicopter
a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°
b) hypotensue = distance between the high school and the helicopter
c) opposite-leg to angle 20° = heigth of the helicopter
d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x
2) triangle to the west of the helicopter
a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°
b) distance between the helicopter and the elementary school = hypotenuse
c) opposite-leg to angle 62° = height of the helicopter
d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x
3) tangent ratios
a) triangle with the helicpoter and the high school
tan 20° = Height / x ⇒ height = x tan 20°
b) triangle with the helicopter and the elementary school
tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°
c) equal the height from both triangles:
x tan 20° = (5 - x) tan 62°
x tan 20° = 5 tan 62° - x tan 62°
x tan 20° + x tan 62° = 5 tan 62°
x (tan 20° + tan 62°) = 5 tan 62°
⇒ x = 5 tant 62° / ( tan 20° + tan 62°)
⇒ x = 4,19 miles
=> height = x tan 20° = 4,19 tan 20° = 1,525 miles
4) Calculate the hypotenuse of this triangle:
hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²
hipotenuse = 4.46 miles
Rounded to the nearest tenth = 4.5 miles
That is the distance between the helicopter and the high school.
