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2 years ago

Solve the quadratic equation. 3x^2 - 5= 70 (Please explain steps)

2 answers:

5 0

Simplifying
3x2 + -5 = 70

Reorder the terms:
-5 + 3x2 = 70
Solving
-5 + 3x2 = 70

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 3x2 = 70 + 5

Combine like terms: -5 + 5 = 0
0 + 3x2 = 70 + 5
3x2 = 70 + 5

Combine like terms: 70 + 5 = 75
3x2 = 75

Divide each side by '3'.
x2 = 25

Simplifying
x2 = 25

Take the square root of each side:
x = {-5, 5} and that’s it.

pickupchik [31]2 years ago

3 0

1.Change the minus sign into a positive
2.add five to both sides
3.do 3 to the 2nd power
4. Divide the two numbers (the one with the variable and the number u got when u added five to it)

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A car travels 2 1/3 miles in 3 1/2 minutes at a constant speed. Write an equation to represent the car travels in miles and minu

Flura [38]

Answer:

The speed of car in miles per minute is $\frac{2}{3}$ miles per minute and

The speed of car in mile per hour is 40 miles per hour,

Step-by-step explanation:

Given as :

The distance cover by car = 2 $\frac{1}{3}$ = $\frac{7}{3}$ miles

The Time taken by car to cover distance = 3 $\frac{1}{2}$ min = $\frac{7}{2}$ min

The speed o car in miles per minute = S miles/min

So, Speed = $\dfrac{\textrm Distance}{\textrm Time}$

Or, S = $\frac{\frac{7}{3}}{\frac{7}{2}}$ mie per min

∴ S = $\frac{2}{3}$ miles per minute

Now, Let The speed of car in miles per hour = x miles/h

So, Time in hour = $\frac{7}{2}$ × $\frac{1}{60}$ = $\frac{7}{120}$ hours

So , Speed = $\dfrac{\textrm Distance}{\textrm Time}$

Or, x = $\frac{\frac{7}{3}}{\frac{7}{120}}$ miles per hours

Or, x = 40 miles per hours

Hence The speed of car in miles per minute is $\frac{2}{3}$ miles per minute and the speed of car in mile per hour is 40 miles per hour, answer

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3 years ago

What function was used to make that pattern

Semenov [28]

Answer:

Step-by-step explanation:

The differences in the terms of f(x) are + 3, + 5, + 7

Since the differences are not constant the relationship is not linear

Note the differences in the differences are + 2, + 2,

The second differences are constant indicating a quadratic relationship

Note the relationship between x and f(x)

x = 1 → 1² = 1 ← require to add 5, that is 1 + 5 = 6 ← value of f(x)

x = 2 → 2² = 4 ← require to add 5, that is 4 + 5 = 9 ← value of f(x)

x = 3 → 3² = 9 ← require to add 5, that is 9 + 5 = 14 ← value of f(x)

x = 4 → 4² = 16 ← require to add 5, that is 16 + 5 = 21 ← value of f(x)

Thus f(x) = x² + 5 → B

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Savatey [412]

-3 - 7 = -10

-2c = -10

-10/ -2 = c

c = 5

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