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gulaghasi [49]
3 years ago
9

Plsss helpppppppppp if you do, you a cool guy or girl

Mathematics
1 answer:
STatiana [176]3 years ago
8 0

9514 1404 393

Answer:

  • Tyler
  • 2 hundredths of a mile

Step-by-step explanation:

The graph is a little difficult to read, but we note that there are 6 grid lines between times that are 2 minutes apart. So, each grid line stands for 2/6 = 1/3 minute.

At the 1-mile mark, the graph crosses 1 grid line above 8 minutes, indicating it takes Tyler 8 1/3 minutes to run 1 mile.

Then in 10 minutes, Tyler will run ...

  distance = speed · time = 1 mile/(8 1/3 min) · 10 min

  = 1/(25/3)·10 = 10·3/25 = 30/25 = 1.2 . . . . miles

__

The equation tells you that Elena runs each mile in 8.5 minutes. To see how far she runs in 10 minutes, we can solve ...

  10 = 8.5x

  x = 10/8.5 ≈ 1.18 . . . . miles

So, Tyler runs farther in 10 minutes by a distance of ...

  1.20 -1.18 = 0.02 . . . . miles

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Answer:

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Step-by-step explanation:

c=30−(0.25)(20)

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Am i correct? calculus
Advocard [28]
Check the picture below.

now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer.  That matters because the derivative of a constant is zero.

now, those are the values when the rocket is 30 feet up above.

\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y
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\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}
\\\\\\
\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\
-------------------------------\\\\


\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\
-------------------------------\\\\
\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}
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8 0
3 years ago
Cual es la sustitución de x/2+3=7
Maslowich

Answer:

conio

Step-by-step explanation:

5 0
3 years ago
Of all the people applying for a certain​ job, 80% are qualified and 20​% are not. The personnel manager claims that she approve
motikmotik

Answer:

69.23% probability that a person is not qualified if he or she was not approved by the manager.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes:

In this problem, we have these following probabilities:

80% probability that a person is qualified

20% probability that a person is not qualified.

90% probability that a qualified person is approved.

10% probability that a qualified person is not approved.

10% probability that an unqualified person is approved.

90% probability that an unqualified person is not approved.

Find the probability that a person is not qualified if he or she was not approved by the manager.

Desired outcomes

Unqualified and not approved.

20% are not qualified. Of those, 90% were not approved. So

0.9*0.2 = 0.18

Total outcomes:

Qualified and not approved or unqualified and not approved.

80% are qualified. Of those, 10% were not approved

20% are not qualified. Of those, 90% were not approved. So

0.8*0.1 + 0.9*0.2 = 0.26

Probability

P = \frac{0.18}{0.26} = 0.6923

69.23% probability that a person is not qualified if he or she was not approved by the manager.

7 0
3 years ago
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