Both triangles that are given (with right angles) lie in plane m, proving that AC is perpendicular to plane m. As angle acd is from a triangle that shares the common perpendicular, it too is a right angle
9514 1404 393
Answer:
yes
Step-by-step explanation:
The figure can be shown to be a parallelogram by showing the sum of endpoints of the diagonals is the same.
A +C = B +D
(0, 6) +(0, -4) = (0, 2) = (3, 5) +(-3, -3) . . . . diagonals bisect each other
If the diagonals of a quadrilateral bisect each other, it is a parallelogram. A parallelogram with a right angle is a rectangle. So, ABCD is a rectangle.
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<em>Additional comment</em>
The midpoint of each diagonal is half the sum of the end point coordinates. That is, the midpoints are (0, 2)/2 = (0, 1). Since calculation of the midpoints requires both sums be divided by 2, we can tell the midpoints are the same if the sums are the same.
Answer:$36 depending on what question is i just assuming how much she has to pay
Step-by-step explanation:
48 divded by 4 is 12. $48-$12 is $36. The $12 is the 1/4 discount.
Solving by substitution:
y = 4x - 3
2x + 7y = 41
Let us substitute the first equation y = 4x - 3 into the second.
2x + 7y = 41
2x + 7(y = 4x -3) = 41
2x + 7(4x -3) = 41
So that's the third option.
I hope this helps.