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djverab [1.8K]
3 years ago
12

(10 - 6i)/(2 + 8i) =?

Mathematics
1 answer:
butalik [34]3 years ago
5 0
Take to i letter in this problem mupliity it together with you would get -48i then take mupliy 10 time 2 would be 20 then after you do that you divided answer divied them an that will give you the answer.

-48/20= 24
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Angela works a basic week of 40 hours and her hourly rate of pay is $12.50. Calculate her weekly wage.
lutik1710 [3]

Answer:

$500

Step-by-step explanation:

6 0
3 years ago
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6у – 6 = 4у + 16<br> A.y=2.2<br> B. y= -2.2<br> C. у= 11<br> D. у= 5
Korvikt [17]

Answer:

C. y=11

Step-by-step explanation:

6y-6=4y+16

6y=4y+22

2y=22

y=11

7 0
3 years ago
Find the Slope:
AveGali [126]

Answer:

4) slope= 0

5) slope =  -  \frac{1}{7}

Step-by-step explanation:

\boxed{ slope = \frac{y _{2} - y_1 }{x_2 - x_1} }

4) Slope

=  \frac{10 - 10}{ - 10 - 3}

=  \frac{0}{ - 13}

= 0

The slope is zero as the line is a horizontal line (since both points have the same y-coordinate of 10).

5) Slope

=  \frac{5 - 4}{2 - 9}

=  \frac{1}{ - 7}

=  -  \frac{1}{7}

Since you have taken (x₁, y₁) to be (9, 4), the value of x₁ should be 9 instead of 2.

6 0
2 years ago
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Find the value of x<br> in the figure below
AlexFokin [52]

Answer:

x = 29

Step-by-step explanation:

I think this because they give you 78 degrees. The angle across from it (3x - 9) must equal 78 degrees as well. So solve as (3x - 9) = 78. 78 + 9 is 87. 87 divided by 3 is 29.

Hope it helps and is correct!

6 0
3 years ago
Find three consecutive integers such that the sum of the first and twice the second is 80 minus three times the third
ivanzaharov [21]

Answer:

The three consecutive integers are 12, 13, 14.

Step-by-step explanation:

Encode the question in an equation. We are given two facts: (1) the three integers are consecutive, and (2) they relate to each other through a sum.

Pick any of the integers (first, second, or third) and call it n. Then write the two others correspondingly in terms of n. I pick the middle one as n, so the three consecutive integers are (n-1), n, (n+1). That's (1). As for (2), here is the fact:

(n-1)+2n = 80-3(n+1)

Lo and behold, one equation with one unknown! Easy to solve for n to give us  the middle integer, n:

(n-1)+2n = 80-3(n+1)\\3n-1= 80-3n -3\\6n =78\\n = 13

The three consecutive integers are 12, 13, 14.

3 0
3 years ago
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