Answer:
False
Explanation:
This is False because when the computer shuts off completely all the data in the ram is deleted
Answer:
The value variable will contain the lowest value in the numbers array.
Explanation:
Given
The given code segment
Required
The result of the code when executed
The illustration of the code is to determine the smallest of the array.
This is shown below
First, the value variable is initialized to the first index element
int value = numbers[0];
This iterates through the elements of the array starting from the second
for (int i = 1; i < numbers.length; i++) {
This checks if current element is less than value.
if (numbers[i] < value)
If yes, value is set to numbers[i]; which is smaller than value
value = numbers[i];
<em>Hence, the end result will save the smallest in value</em>
Answer:
- with(open("numbers.txt")) as file:
- data = file.readlines()
- runsum = 0
- largest = 0
-
- for x in data:
- if(int(x) > largest):
- largest = int(x)
- runsum += largest
-
- print(runsum)
Explanation:
The solution code is written in Python 3.
Firstly, open a filestream for numbers.txt (Line 1) and then use readlines method to get every row of data from the text files (Line 2).
Create a variable runsum to hold the running sum of number bigger than the maximum value read up to that iteration in a for loop (Line 3).
Use a for loop to traverse through the read data and then check if the current row of integer is bigger than the maximum value up to that point, set the current integer to largest variable and then add the largest to runsum (Line 6 - 9).
At last display the runsum to console terminal (Line 11).
Answer:
The pickup diagram for the Cardioid (heart-shaped) microphone pattern tells you is that the microphone is most sensitive to sound coming in from the front (where the blue arrow is), and will tend to “refuse” sound coming in from the other side (the red arrow points to that part).
Explanation:
The only way without a while loop and no method I can think of is use switch with every possible variation of the four digit binary which is 15.
Here is the starter code:
import java.util.Scanner;
public class MyClass {
public static void main(String args[]) {
Scanner sc = new Scanner(System.in);
int digit = sc.nextInt();
switch(digit) {
case 0000:
System.out.println("0");
break;
case 0001:
System.out.println("1");
break;
case 0010:
System.out.println("2");
break;
case 0011:
System.out.println("3");
break;
case 0100:
System.out.println("4");
break;
… (fill in other cases)
}
}
}
Use this link: https://www.electronics-tutorials.ws/binary/bin_3.html
There might be a better way, but without loops or methods this is all I got.
