N = # of chips = 100
M = # of defective chips = 8
S = sample size = 10
a) P(X ≥ 1) = 1 - [((N-M)! / (N-M-S)!) / (N! / (N-S)!)] ≈ 0.583
b) P(X = 10) = 0 (because S > M)
c) P(X = 9) = 0 (because 9 > M)
d) P(X = 0) = 1 - P(X ≥ 1) ≈ 0.417
Answer:

Step-by-step explanation:
In order to isolate D, multiply by T on both sides.
Answer: 0.8 ------ 1,600
Step-by-step explanation:
this answer is $1.90
im not sure of the work to get to the answer