Answer:
That's two half lives. 5/8 * 2 * 2 = 20/8 = 5/2 pounds7/8 * 2 * 2 = 28/8 = 7/2 pounds
Step-by-step explanation:
Brainliest plz?
If you need further help on how they got the answer, this equation will take more time, but it will also help you understand these types of problems. Part÷Whole=Percent÷100
Part= X because it is what you are trying to find.
Whole=250 because it is what you are taking the percentage of.
Percent=80
Now you have:
X÷250=80÷100
Set this up in fraction form and cross multiply.
You get:
100x=250×80
250×80=20,000
100x=20,000
X=200
Answer:
7 + 8 = 7 + 7 + 1.
Step-by-step explanation:
We know that, 'double plus one facts' is used to make the addition of numbers easy.
For e.g. we have 8 + 9 = 17. This addition can also be done as 8 + 8 + 1 = 17 i.e. we write first term twice and add 1 to get the result.
Hence, we give the name to this type of addition as 'double plus one'.
Now, we have to use this fact for 7 + 7.
So, we consider 7 + 8 = 15.
Therefore, 7 + 8 can be written as 7 + 7 + 1
Hence, the double plus one facts for 7 + 7 is 7 + 8 = 7 + 7 + 1.
9x^2-49
It equals:
<span>(<span><span>3x</span>+7</span>)</span><span>(<span><span>3x</span>−7</span><span>)
Hope this helps!
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Answer:
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So
X = 8.6
has a pvalue of 0.8413
X = 6.4
has a pvalue of 0.1587
0.8413 - 0.1587 = 0.6826
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
