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KonstantinChe [14]
2 years ago
12

Whitney and Destiny hung out at the mall on Saturday. They spent 45 minutes shopping for clothes and 1 hour at the food court. T

hen they spent 30 minutes at the video arcade before heading home. It was 12:45 P.M. when Whitney and Destiny left the mall. What time did they start shopping for clothes?
Mathematics
1 answer:
mojhsa [17]2 years ago
4 0

Answer:

11.15 i think

Step-by-step explanation:

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Saturn’s rings span up to about (7.5 · 10-1) of the distance between the Earth and its moons. If Saturn’s rings span up to (2.82
RUDIKE [14]
2.82 × 10^5 = (7.5×10^-1) × Length between the earth and the moon
Length between the earth and the moon = (2.82×10^5)÷(7.5×10^-1)                                                                     = 376000                                                                     = 3.76×10^5
i think this is correct hope it helps. 
7 0
3 years ago
Read 2 more answers
Let f(x)=2x−1. If 3f(a)=15, what is the value of f(2a)?
Misha Larkins [42]
The answer is 7.

f(a) = 2a-1, 3f(a) = 3(2a-1) = 15 -> a=2 so f(2a)=f(4)=7
3 0
2 years ago
A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the
grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = \frac{diameter}{2}=\frac{66}{2} =33 \ mm

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = \frac{4}{3}\pi r^3

Now Volume of Gumball = \frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = \frac{diameter}{2}=\frac{58}{2} =29 \ mm

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = \frac{4}{3}\pi r^3

So Volume of gumball's spherical hollow core = \frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = 150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = 48347.6\ mm^3

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0
3 years ago
Identify the usual level of measurement for each of the following A. year in school B. IQ scores C. life expectancy D. fatigue E
Mashutka [201]

Answer:

The answer is C

Step-by-step explanation:

4 0
2 years ago
You have been averaging 55 sales per day. Per our new policy, everyone needs to increase his or her sales per day by 10% in the
Mariulka [41]
To find your new number of sales per month, you will need to find the number of sales you have per month (based on 30 days per month).  

55 x 20 = 1650 sales.

Than, you will need to calculate what 10% of this is and add it to your original sales number.

0.1 (10%) x 1650 = 165

1650 + 165 = 1815

You will need approximately 1815 sales based on the 30 day month.
8 0
2 years ago
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