Answer:
Circumference=25.13 Area=50.27
Substitution is best to use one one or both equations is already solved for one of the variables. Elimitation can be use if all variables have a coefficient other than 1.
Since it's p over four, which is a fraction, multiply each side by four. p = 20
Answer:
X=62
Step-by-step explanation:
X=62 because the side where x is and where the other degree is, they are congruent. And since you have to add 12 it would have to be 62 to be equal to 74.
The answer is D.
We know that a rectangle has two widths that are equal and two lengths that are equal. One width is 22, so the other one is also 22.
If you wanted to find the lengths, you would add both widths together (same as multiplying a width by two) and add that to the two lengths equaled to the perimeter.
So, 22 * 2 + 2x = perimeter of rectangle. We added all four sides together.
We know that the perimeter is at least 165, so 22 * 2 + 2x = 165. Here's the twist. They want the most minimum possible length. So, what answer choice gives you 165 or less for the most minimum or smallest length while still getting to 165?
That is D.
22 * 2 + 2x < = 165.
Hope this helped!
