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Fantom [35]
2 years ago
11

Probability check point 6 , you have a bag containing 2 red balls, 4 green balls, and 5 purple balls. you draw one ball from the

bag: it's green. call this draw 0. keep this ball and continue drawing (without replacement) until you get another green ball. call these draws 1, 2...k. what is the probability that you don't draw another green ball until draw 3
Mathematics
1 answer:
natta225 [31]2 years ago
8 0
There are now 10 balls in the bag since you took 1 green out
There are now 3 greens in the bag
3/10 is the chance you pick a green,so 7/10 is the chance you DIDNT pick a green ball for the first round
Second round:-1 ball that is not green now the number of ball is 9
10+9=19

(# of green balls still in the bag)3/19 final answer 
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Since we have two possible pieces of information and 2 items to solve for, we know this is a system of equations.
Our first piece of information is that our shorter leg (s) is 2 feet shorter than our longer leg (l). This can be written as s=l-2.
Our second piece of information is that using the Pythagorean theorem that our shorter leg squared plus our longer leg squared is equal to our hypotenuse squared. This can be represented by s^2+l^2=10^2. Now we can solve.
We have already isolated for s in our first equation, so we can substitute l-2 in.
(l-2)^2+l^2=10^2
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2l-2=10
2l=12
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Now we can substitute in for s in our simpler equation
s=6-2
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We now know that using our knowledge of systems of equations, the side lengths of this right angle triangle are 6 and 4.
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