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masha68 [24]
2 years ago
14

The equation 12x² + 4kx + 3 = 0 has real and equal roots, if

Mathematics
1 answer:
sleet_krkn [62]2 years ago
8 0

Answer:

k=\pm3

Step-by-step explanation:

[...] if you can write the LHS as a perfect square, or if you can't spot a factorization of it right away, if and only if the discriminant \Delta = b^2-4ac (or, if b is an even number, 1/4 of it) is zero.

<u>I see it! I see it!</u>

Stare at it for a while. First term is 3(2x)^2, third term is 3(1)^2, we are missing a double product, but we can play with k. For the LHS to be 3(2x\pm1)^2 = 3(4x^2\pm4x+1) = 12x^2\pm12x+3 you just need 4k= \pm12 \rightarrow k=\pm3.

<u>I don't see it...</u>

Then number crunching it is. Set the discriminant to 0, solve for k

\frac{\Delta}4 = 4k^2-12\cdot 3 =0 \rightarrow 4k^2=36 \\k^2 = 9 \rightarrow k=\pm3

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solong [7]

Answer:

The end of the flagpole is 50.79 ft away from the base of the pole.

Step-by-step explanation:

The problem is represented by the diagram below.

The broken flagpole forms the shape of a right angled triangle. We need to find one of the sides of the triangle, the adjacent (x).

The hypotenuse is the broken part of the flagpole (53 ft), while the opposite is the part of the flagpole that is still stuck to the ground (28 ft).

Using Pythagoras theorem, we have that:

hyp^2 = adj^2 + opp^2

=> 53^2 = x^2 + 28^2

3364 = x^2 + 784\\\\=> x^2 = 3364 - 784\\\\x^2 = 2580\\\\x = \sqrt{2580}\\ \\x = 50.79 ft

The end of the flagpole is 50.79 ft away from the base of the pole.

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3 years ago
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FromTheMoon [43]

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taurus [48]
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Find two numbers that have a sum of -2 and a product of -48 (please show work if possible)​
andreev551 [17]

Answer: -8 and 6

Step-by-step explanation:

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for two number to have a sum of -2, the greater number must be the negative number, and both numbers should have be two values apart (ex. 6 and 8, 3 and 5, 12 and 14, etc.). In this case, 8 would have to be negative whereas 6 will be left positive.

and then we check:

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3 years ago
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