Question

The vertices of a rectangle are listed below.

Answer 1

Answer:

Therefore Area of Rectangle IJKL is 108 unit².

Step-by-step explanation:

Given:

The vertices of a Rectangle are  

I ( 6 , 8)

J ( 6 , -1)

K ( -6 , -1)

L ( -6 ,8)

To Find:

Area of Rectangle IJKL= ?

Solution:

First we will find the Length and Width of Rectangle by Distance Formula ,

$l(IJ) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting the values we get

$l(IJ) = \sqrt{((6-6)^{2}+(-1-8)^{2} )}$

$l(IJ) = \sqrt{((0)^{2}+(-9)^{2} )}\\l(IJ)=\sqrt{81}=9\ unit$

Similarly for JK we will have,

$l(JK) = \sqrt{((-6-6)^{2}+(-1-(-1))^{2} )}\\l(JK)=\sqrt{144}=12\ unit$

Now

$Length=IJ =9\ unit\\Width=JK=12\ unit$

Now Area of Rectangle is given by

$\textrm{Area of Rectangle}=Length\times Width$

Substituting the values we get

$\textrm{Area of Rectangle IJKL}=9\times 12=108\ unit^{2}$

Therefore Area of Rectangle IJKL is 108 unit².