What is the equation of a line that is perpendicular to y=0.25x-7 and passes through the point -6,8
1 answer:
Answer:
The equation ls: y = -4x - 16
Step-by-step explanation:
Given the point (-6, 8)
Given the line y = .25x - 7
Use a fraction:
y = 1/4x - 7
The slope is 1/4 (or .25)
The slope of a perpendicular line is the negative inverse or -4.
Use the point slope form and substitute:
y - y1 = m(x - x1)
y - 8 = -4(x - (-6))
y - 8 = -4x - 24
y = -4x - 16
Proof:
f(-6) = -4(-6) - 16
= 24 - 16
= 8, giving (-6, 8)
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