Question

What is the equation of a line that is perpendicular to y=0.25x-7 and passes through the point -6,8

Answer 1

Answer:

The equation ls: y = -4x - 16

Step-by-step explanation:

Given the point (-6, 8)

Given the line y = .25x - 7

Use a fraction:

y = 1/4x - 7

The slope is 1/4 (or .25)

The slope of a perpendicular line is the negative inverse or -4.

Use the point slope form and substitute:

y - y1 = m(x - x1)

y - 8 = -4(x - (-6))

y - 8 = -4x - 24

y = -4x - 16

Proof:

f(-6) = -4(-6) - 16

= 24 - 16

= 8, giving (-6, 8)