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Korolek [52]
3 years ago
13

How do u solve X^3y divided by Y^4x

Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0
All I can say to help you with this, is to rewrite the division as a fraction,
x^3y / y^4x

Sorry, if it's not much help.
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1+1
Bezzdna [24]

Answer:

2

Step-by-step explanation:

Well you should count with fingers, one finger and one finger, two fingers

8 0
3 years ago
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PLZ ANSWER ASAP THOROUGHLY FOR BRANLIEST AND HIGH RAITINGS!!!
Tom [10]

Answer:

Step-by-step explanation:

h=7mm

3 0
3 years ago
How do you solve for X and round the nearest tenth​
Advocard [28]

Answer:

x = 7.3

Step-by-step explanation:

When solving for missing sides using angles, use trig functions.  

We have the angle 63° to use.  

We are given the hypotenuse of the triangle, as well as the side adjacent to the angle, so we can use the cos function.

Cos T = (adjacent side)/(hypotenuse)

Here we know 'T' and the hypotenuse, so plug them in and solve

Cos 63° = x/16

  (16)Cos 63° = x    (multiply both sides by 16 to isolate 'x')

      7.263847996 = x           (use your calculator to solve the left side)

      7.3 = x   (rounded to the nearest 10th)

7 0
3 years ago
Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n
Darina [25.2K]

Recall that for |<em>x</em>| < 1, we have

\displaystyle \frac1{1-x} = \sum_{n=0}^\infty x^n

Differentiating both sides gives

\displaystyle \frac1{(1-x)^2} = \sum_{n=0}^\infty nx^{n-1} = \sum_{n=0}^\infty (n+1)x^n

and multiplying both sides by 8 gives the series for <em>f(x)</em> :

f(x)=\displaystyle \frac8{(1-x)^2} = \boxed{8\sum_{n=0}^\infty (n+1)x^n}

and this converges over the same interval, |<em>x</em>| < 1, so that the radius of convergence is 1.

4 0
3 years ago
How do you solve this problem? population proportion is to be estimated from a sample of 400 with a sample proportion of 0.1. Ap
Ivan

Answer:

(0.0706, 0.1294)

Step-by-step explanation:

Confidence interval of a proportion is:

CI = p ± CV × SE

where p is the proportion,

CV is the critical value (z score or t score),

and SE is the standard error.

The sample is large enough to estimate as normal.  For 95% confidence level, CV = z = 1.96.

Standard error for a proportion is:

SE = √(pq/n)

SE = √(0.1 × 0.9 / 400)

SE = 0.015

The confidence interval is:

CI = 0.1 ± (1.96)(0.015)

CI = (0.0706, 0.1294)

Round as needed.

6 0
3 years ago
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