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3 years ago

Ms. McCullough bought a bunch of bananas. If she ate 2/8

Mathematics

1 answer:

DaniilM [7]3 years ago

4 0

Answer:

1/2

Step-by-step explanation:

that's the answer because 2/8-1/4 is 1/2

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5 bullets in a 6 bullet barrell, what are your chances of dying on the first trigger pull?

Ostrovityanka [42]

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3 years ago

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The price of a television is $245. The sales tax rate is 8%. What is the amount of the sales tax?

Elza [17]

Answer:

$19.60

Step-by-step explanation:

Take the amount and multiply by the tax rate to determine the sales tax

tax = 245 * 8%

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tax =245*.08

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State the slope, y intercept and a linear equation from the given graph. Please help

Luba_88 [7]

Answer:

below

Step-by-step explanation:

y = -2x/3 - 4

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2 years ago

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Kate found a new knitting pattern she's been wanting to try. It makes a rainbow-striped 60-inch scarf. Last month, it took her 1

telo118 [61]

Answer: 4 weeks (1 month)

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7 0

3 years ago

Construct a 90% confidence interval for μ1-μ2 with the sample statistics for mean calorie content of two bakeries' specialty pi

DIA [1.3K]

Answer:

The 90% confidence interval for the difference in mean (μ₁ - μ₂) for the two bakeries is; (49) < μ₁ - μ₂ < (289)

Step-by-step explanation:

The given data are;

Bakery A

$\overline x_1$ = 1,880 cal

s₁ = 148 cal

n₁ = 10

Bakery B

$\overline x_2$ = 1,711 cal

s₂ = 192 cal

n₂ = 10

$\left (\bar{x}_1-\bar{x}_{2} \right ) - t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}< \mu _{1}-\mu _{2}< \left (\bar{x}_1-\bar{x}_{2} \right ) + t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}$

df = n₁ + n₂ - 2

∴ df = 10 + 18 - 2 = 26

From the t-table, we have, for two tails, $t_c$ = 1.706

$\hat{\sigma} =\sqrt{\dfrac{\left ( n_{1}-1 \right )\cdot s_{1}^{2} +\left ( n_{2}-1 \right )\cdot s_{2}^{2}}{n_{1}+n_{2}-2}}$

$\hat{\sigma} =\sqrt{\dfrac{\left ( 10-1 \right )\cdot 148^{2} +\left ( 18-1 \right )\cdot 192^{2}}{10+18-2}}= 178.004321469$

$\hat \sigma$ ≈ 178

Therefore, we get;

$\left (1,880-1,711 \right ) - 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}< \mu _{1}-\mu _{2}< \left (1,880-1,711 \right ) + 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}$

Which gives;

$169 - \dfrac{75917\cdot \sqrt{35} }{3,750} < \mu _{1}-\mu _{2}< 169 + \dfrac{75917\cdot \sqrt{35} }{3,750}$

Therefore, by rounding to the nearest integer, we have;

The 90% C.I. ≈ 49 < μ₁ - μ₂ < 289

4 0

3 years ago