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Naddika [18.5K]
3 years ago
15

The following section is a statement from the rental agreement Tim signed when he rented his car this past weekend.

Mathematics
1 answer:
harkovskaia [24]3 years ago
8 0
Bbbbbbbbbbb????????????!??!
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Can anyone solve the circled numbers?If not just please solve whatever you can.Im so tired
EastWind [94]

Answer:

36. The absolute value of |97| is 97. Remember, the absolute value of a number is how far away the number is from zero.

40. I think that says |-23/56| .... if so, I'm pretty sure you can just say 23/56... not too sure though. Because, yes, technically this number is 23/56 away from zero... just not sure if that is the final way you should answer.

44. Answer: Wayne, MI (-0.2)

Explain: Wayne, MI had the least percent change in pop. because it is the closest option to 0, it only decreased 0.2 percent.

48.

|43-4a| + 51

|43-4(6)| + 51

|43-24| + 51

|19| + 51

19 + 51

=70

52.

7.4 + |y-2.6|

7.4 + |3.2-2.6|

7.4 + |0.6|

7.4 + 0.6

=8

56.

|-c| + (2+1/2)

|-5/4| + (2+1/2)

|5/4| + (2+1/2)

|1 1/4| + (2+1/2)

1 1/4 + (2+1/2)

1 1/4 + (2 1/2)

1 1/4 + 2 1/2

1 1/4 + 2 2/4

=3 3/4

<u>That</u><u> </u><u>is</u><u> </u><u>all</u><u> </u><u>I</u><u> </u><u>can</u><u> </u><u>do</u><u> </u><u>for</u><u> </u><u>you</u><u>!</u><u> </u><u>I</u><u> </u><u>hope</u><u> </u><u>I</u><u> </u><u>helped</u><u> </u><u>:</u><u>)</u><u> </u>

4 0
3 years ago
A newspaper carrier has $3.65 in change he has four more quarters then dimes but two times as many nickels as quarters how many
77julia77 [94]

Answer:

The number of quarter coins is 9, the number of dime coins is 5 and the number of nickel coins is 18

Step-by-step explanation:

Let

x ----> the number of quarter coins

y ---> the number of dime coins

z ---> the number of nickel coins

Remember that

1\ quarter=\$0.25

1\ dime=\$0.10

1\ nickel=\$0.05

we know that

0.25x+0.10y+0.05z=3.65 ----> equation A

x=y+4

y=x-4 ----> equation B

z=2x ----> equation C

Solve the system by substitution

substitute equation B and equation C in equation A

0.25x+0.10(x-4)+0.05(2x)=3.65

solve for x

0.25x+0.10x-0.40+0.10x=3.65

0.45x=3.65+0.40

0.45x=4.05\\x=9

<em>Find the value of y</em>

y=x-4

substitute the value of x

y=9-4=5

Find the value of z

z=2x

z=2(9)=18

therefore

The number of quarter coins is 9, the number of dime coins is 5 and the number of nickel coins is 18

4 0
4 years ago
Find the length of side a in the right triangle below.
Olin [163]

Answer:

I'm assuming that a is the hypotenuse (Longest side)

Step-by-step explanation:

22.67 is the answer

If a isn't the hypotenuse (Longest side) then let me know in the comments then I will comment the right answer for you <3

3 0
4 years ago
<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B
inysia [295]

\large \bigstar \frak{ } \large\underline{\sf{Solution-}}

Consider, LHS

\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered}  \\  \\  \text{So, using this identity, we get} \\  \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered}  \\

So, using this identity, we get

\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

can be rewritten as

\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}

<h2>Hence,</h2>

\begin{gathered} \\ \rm\implies \:\boxed{\sf{  \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}

\rule{190pt}{2pt}

5 0
3 years ago
-x^4y^2+7x^3y^3-3xy^5+2x^2y^4 in descending powers of x
muminat

Answer:

  -x^4y^2 +7x^3y^3 +2x^2y^4 -3xy^5

Step-by-step explanation:

The powers of x in the terms of the given expression are ...

  4, 3, 1, 2

so, we want to swap the last two terms to put them in the desired order:

  -x^4y^2 +7x^3y^3 +2x^2y^4 -3xy^5

6 0
3 years ago
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