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xxMikexx [17]
3 years ago
12

5004300 in standard form

Mathematics
2 answers:
iogann1982 [59]3 years ago
8 0

Answer:

five million four thousand three hundred

Step-by-step explanation:

Yuliya22 [10]3 years ago
6 0
Five million four thousand three hundred
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Help please <br> Graph ​y&lt;1−3x​.
mash [69]
It should be #4, dashed line and left side shaded
8 0
3 years ago
43 milk jugs are in a fridge with 11 that are spoiled. 5 jugs are randomly selected. what are the odds that the first two are go
malfutka [58]

Answer:

0.85% probability that the first two are good and the last three are spoiled

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the first two jugs is not important, as is not the order in which the last three are selected. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes:

2 spoiled, from a set of 43-11 = 32.

3 spoiled, from a set of 11.

So

D = C_{32,2}*C_{11,3} = \frac{32!}{2!(32-2)!}*\frac{11!}{3!(11-3)!} = 982080

Total outcomes:

5 jugs from a set of 43.

T = C_{43,5} = \frac{43!}{5!(43-5)!} = 115511760

Probability:

p = \frac{D}{T} = \frac{982080}{115511760} = 0.0085

0.85% probability that the first two are good and the last three are spoiled

4 0
3 years ago
Identify a possible first step using the elimination method to solve the system and then find the solution to the system. 3x - 5
irina1246 [14]

ans is b...multiply eqn 1 by -2 and eqn 2 by 3

=》 -6x + 10y = 4...eqn 3

=》 6x + 3y = 9...eqn 4

add eqn 3 and 4...

=》13y = 13

=》y =1 and x = 1

5 0
3 years ago
What is x in 1/150/1/200x2=x
choli [55]

Answer:

6.66666667E-5

hope this helped a bit!

5 0
3 years ago
Given: // CDAB , ∠≅∠ DB and ≅ EDBF . Prove: Δ ABF ≅ Δ CED
SCORPION-xisa [38]

Given: line segment AB // to line segment CD, ∠B ≅∠D and line segment BF ≅ to line segment ED. Prove: Δ ABF ≅ Δ CED.

Follow the matching numbers on the statement versus reason chart.

Statement:

1. line segment AB // to line segment CD.

2. ∠B ≅∠D

3. line segment BF ≅ to line segment ED.

4. ∠A ≅∠C

5. Δ ABF ≅ Δ CED

 

Reason:

1. Given

2. Given

3. Given

4. Alternate interior angles are congruent.

5. Corresponding parts of congruent triangles are congruent.

4 0
3 years ago
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