Answer:
Percentage change in interest groups between 1959 (500) & 1995 (600) = 20%
Step-by-step explanation:
Percentage change = <u>Change ie (New - Old) </u> x 100
Old value
Suppose -
Number of interest groups in 1959 = 500
Number of interest groups in 1995 = 600
Percentage change = [ (600 - 500) / 500 ] x 100
( 100 / 500 ) x 100 = 20%
Answer:
17,19,21
Step-by-step explanation:
let the first odd number be "x"
formular : (x)+(x+2)+(x+4).
3x+6=57
3x=57-6
3x=51
x=51/3
x=17
apply the formular.
17,(17+2),(17+4)
17,19,21.
You have to double 1 and 50 to get 2 and 100
1:50 = 2:100
1x2=2
50x2=100
So the statement, <em>if she studied for 2 hours, she would have gotten 100%</em>, makes sense
Hope this helps!
As it has been given that 
, 
.
We need to find the value of the following:
(i) 
, substituting the value of 'x' and 'y' in the expression, we get:
So, 
(ii) 
, substituting the value of 'x' and 'y' in the expression, we get:
So, 
(iii) 
, we need to substitute the value of 'x' and 'y' in the expression, for this, we can use distributive property of multiplication that says,
Using the distributive property of multiplication:
Now, we know that 
We get, 
Therefore, =
.
(iv) We have, 
, we need to substitute the value of 'x' and 'y' in the expression, we get:
Again, we can use distributive property of multiplication that says,
So,
since, 
we get,
Therefore,
Answer:
l = (P-2w)/2
Step-by-step explanation:
P = 2l + 2w
move 2w to the left to leave the l variable by itself
P - 2w = 2l
divide by 2 on both sides to leave l by itself
(P - 2w) / 2 = l or l = (P - 2w) / 2
