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mamaluj [8]
2 years ago
14

Tamara bought a $22 mailbox using a 10% off coupon David bought an identical mailbox for $19.95 at a different store

Mathematics
1 answer:
MAVERICK [17]2 years ago
4 0

Answer:David bought an identical mailbox for $ 19.95 at a different store.

Step-by-step explanation:

David bought an identical mailbox for $ 19.95 at a different store. you can buy a same mailbox but for different prices you have 22 dollars you have a 110 percent off you dont have enough

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15 POINT 1 QUESTION<br> ITS ALL UP TO YOU!!!!
Anni [7]

First, we can simplify the left side. (6+8x)/2 is equal to 3 + 4x. We can put the equation together at this point.

3 + 4x = 5x

we can subtract 4x from both sides to get our final answer,

3 = x, or x = 3. :)

8 0
3 years ago
Margaret deposits $1,000 in a savings account that pays 1.4% interest compounded
ozzi

Answer:

The balance after 1 year is;

$1,014.05

Step-by-step explanation:

To do this, we use the compound interest formula

That will be ;

A =P (1 + r/n)^nt

A is the amount generated which we want to calculate

r is the rate = 1.4% = 0.014

P is the amount deposited = $1,000

n is the number of times it is compounded annually which is 2 (semi-annually means 2 times in a year)

this the number of years which is 1

we have this as:

A = 1,000( 1 + 0.014/2)^(2*1)

A = 1,000(1 + 0.007)^2

A = 1,000(1.007)^2

A = $1,014.05

8 0
3 years ago
Brenna writes a product of six negative factors. She uses
IgorC [24]

Answer: (A) The product of two numbers with the same sign is positive.

Since the numbers in each pair have the same sign, the product will be positive.

3 0
3 years ago
Read 2 more answers
Please helpppp! i’ll mark brainliest
Fiesta28 [93]

Answer:

from what i see i see thats its D

if not im sorry but i hope i got it right

Step-by-step explanation:

8 0
3 years ago
(Uniform) Suppose X follows a continuous uniform distribution from 4 to 11. (a) Write down the PDF of X. (b) Find P(X ≤ 7). Roun
love history [14]

Answer:

a) f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11

b) P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286

c) P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857

d) P(X >5 | X \leq 7)

And we can find this probability with this formula from the Bayes theorem:

P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5

Step-by-step explanation:

For this case we assume that the random variable X follows this distribution:

X \sim Unif (a=4, b =11)

Part a

The probability density function is given by the following expression:

f(x) = \frac{1}{b-a} , a \leq x \leq b

f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11

Part b

We want this probability:

P(X \leq 7)

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}= \frac{x-4}{11-4}

And replacing we got:

P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286

Part c

We want this probability:

P(5 < X \leq 7)

And we can use the CDF again and we have:

P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857

Part d

We want this conditional probabilty:

P(X >5 | X \leq 7)

And we can find this probability with this formula from the Bayes theorem:

P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5

7 0
3 years ago
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