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Vladimir79 [104]
3 years ago
6

Identify the maximum and minimum values of the function y = 8 cos x in the interval [-2π , 2π].

Mathematics
1 answer:
Veronika [31]3 years ago
3 0
Hello here is a solution ; 

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Can someone help me plz Xd
stira [4]

Answer:

-2497

Step-by-step explanation:

Sn=n/2[2a+(n-1)d]

=22/2[2*-40+(22-1)d]

=11(2*-40+(21*-7)

= -2497

8 0
3 years ago
19 degrees and a little over the top of my day and
Neporo4naja [7]
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3 0
2 years ago
Help me 15 points plz fast
yaroslaw [1]

Answer:

The two numbers marked on the number line are -5 and 7.

Two inequalities to compare the marked numbers on the number line:

-5 < 7  or 7 > -5

The <u><em>written form</em></u> of the two inequalities are:

-5 < 7 : Negative five is <u>less than</u> positive seven.

7 > -5 : Positive seven is <u>greater than</u> negative five.

6 0
2 years ago
Read 2 more answers
Which system of equations is graphed on this coordinate plane​
Allisa [31]

Answer:

y=(3x/2)+3 and y=(-1x/2)-1

Step-by-step explanation:

So what I did was use rise/run to find the slope of the equation. Let's focus on the line going from the bottom left to the top right corner. For this line, I would start on (-2,0) which is one of the points plotted on your number line and count how much it is away from (0,3). You should get 3 units. After this, count how much it is to the right which is 2 units. Now, use rise/run to find the slope. 3/2, therefore the slope of the line is 3x/2.  Now all we need is the y-int. For the Y int, all we have to do is see where the line touches the Y-axis which in this case is at (0,3). So your y-int would be 3. Now we can use this information to craft an equation in the form y=mx+b, m being the slope and b  being the y int. We should get y=(3x/2)+3. Now repeat this with the other line to find the equation, but be careful!!! It has a negative slope.

7 0
3 years ago
Someone help please?! Need right answers only don’t come for the points will mark brainliest
Kaylis [27]
Hi there!

These can probably be done on your own. You just gotta know what to do! :)

Let's take #1 for example. You (or maybe a classmate/teacher showed you?) plotted the points. Mark each point with the given letter, so you don't get lost. Then, you reflected it over the y-axis.

Think of it as a mirror. Say you held a picture of a rhombus up to it. You would see the rhombus, yourself, and whatever was in the background reflected back at you. You step closer, the image steps closer. You turn the rhombus, and the image also turns. This principle can be used here!

So, keep doing what you're doing. Here's a step-by-step:

1.) Plot each point, and mark its name. For example, 'B' is (-6,7), and you write 'B' next to the point.

2.) Double check the point are exactly where they need to be

3.) Connect each point with a straight line. You can use a ruler, student ID, whatever as a straightedge, but it looks neater

4.) Draw a line for the axis. For example, if y=0, draw a straight line again there. (hint: that's the y-axis!)

5.) Double check that everything is right so far again. This is easy to mess up!

6.) Reflect each point over the axis. Another example, (-3, 2) becomes (3, 2). Mark this with an apostrophe (') to signal the point as prime, or the reflected point. For example, B becomes B' (B prime)

7.) Check one final time

If you found this especially helpful, I'd appreciate if you'd vote me Brainliest for your answer. I want to be able to assist more users one-on-one! :)
6 0
2 years ago
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