Evaluate 4x squared - 8x + 8 when x = -6

Mathematics

1 answer:

Romashka [77]3 years ago

4 0

Answer:

Step-by-step explanation:

√4×-6+8×6+8=2×-6+48+8

-12+48+8

=48

You might be interested in

Calculate the angles of a parallelogram if the sum of the three angles is 310°

Gennadij [26K]

9514 1404 393

Answer:

adjacent angles are 50° and 130°

Step-by-step explanation:

The sum of all 4 angles in a parallelogram is 360°, so the fourth angle must be ...

360° -310° = 50°

Adjacent angles are supplementary, so the other two angles must be ...

180° -50° = 130°

The angles in the parallelogram are either 50° or 130°. Adjacent angles are different.

8 0

3 years ago

If p q r is prime numbers such that pq+r=73, what is the least possible value of p+q+r

Jobisdone [24]

The answer to this question would be: p+q+r = 2 + 17 + 39= 58

In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number.

There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73

The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39

p+q+r = 2 + 17 + 39= 58

6 0

3 years ago

Read 2 more answers

Give four rational numbers betwee1by2 and 6 by 7

MA_775_DIABLO [31]

Answer:

Therefore four rational numbers between 1 and 2 are 9/8, 5/4, 3/2, and 7/4 Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find the inverse for each relation: 1. {(1,-2), (2, 3),(3, -3),(4, 2)}

andrey2020 [161]