Prove that tanx+secx/ secx (1+ tanx/secx)=1
1 answer:
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Given end points of diameter,
(x1,y1)=(-3,-4)
(x2,y2)=(0,0)
Now,
the equation of circle is,
(x-x1)(x-x2)+(y-y1)(y-y2)=0
or, (x+3)(x-0)+(y+4)(y-0)=0
or, x^2 +3x +y^2 +4y =0
or, x^2 +y^2 +3x + 4y=0
which is in the form of x^2 +y^2 +2gx +2fy + c=0
where,
g=3/2
h=2
c=0
Now,
Keywords:
<em>Division, quotient, polynomial, monomial </em>
For this case we must solve a division between a polynomial and a monomial and indicate which is the quotient.
By definition, if we have a division of the form: , the quotient is given by "c".
We have the following polynomial:
that must be divided between monomy
, then:
represents the quotient of the division:
Thus, the quotient of the division between the polynomial and the monomial is given by:
Answer:
The quotient is:
Option: A
Answer:
:)
Step-by-step explanation: