the Pythagorean Theoremproof of let ΔABC be a right triangle. and sinA=a/c, and cosA= b/ca opposite side of the angle Ab the adjacent side of the angle Aand c is the hypotenuswe know that sin²A +cos²A= (a/c)²+ (b/c) ², but sin²A +cos²A=1so, a²/c²+ b²/c ²=1 which implies a²+ b²=c² the answer is Transitive Property of Equality proof the right triangles BDC and CDA are siWe start with the original right triangle, now denoted ABC, and need only one additional construct - the altitude AD. The triangles ABC, DBA, and DAC are similar which leads to two ratios:AB/BC = BD/AB and AC/BC = DC/AC.Written another way these becomeAB·AB = BD·BC and AC·AC = DC·BCSumming up we getAB·AB + AC·AC= BD·BC + DC·BC = (BD+DC)·BC = BC·BC.so not in the proof is Transitive Property of Equality
< right angle is the right answer
Answer:
-1 ≤ x ≤8 (don't care about the equal sign)
Step-by-step explanation:
-6+4≤2x≤12+4
=-2≤2x≤16
=-1≤x≤8
9514 1404 393
Answer:
27 cm³
Step-by-step explanation:
The surface area of a cube is ...
SA = 6s²
Then the edge length is ...
54 cm² = 6s² . . . . . please note that cm³ is not the appropriate unit for area
9 cm² = s² . . . . . .divide by 6
3 cm = s . . . . . . . take the square root
The volume of a cube is ...
V = s³
V = (3 cm)³ = 27 cm³
The volume of the cube is 27 cm³.
-8 + k = -17
k = -17 + 8
k = 8 -17
k = -9
