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pogonyaev
2 years ago
14

Someone plz help me :(

Mathematics
1 answer:
jeka942 years ago
7 0

Answer:

Step-by-step explanation:

b

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Please answer quickly I need the help
Nat2105 [25]

Answer:

g=6

Step-by-step explanation:

8 0
3 years ago
I have having a problem with this equation 3(-2-3x) = -9x-4
inn [45]

Answer:

3(-2-3x) = 9x-4

-6-9x = 9x-4

-6+6-9x = 9x-4+6

-9x = 9x+2

-9x-9x = 9x-9x+2

-18x = 2

-18x÷(-18) = 2÷(-18)

x = -(1/9)

Thank you

BY GERALD GREAT

6 0
3 years ago
HELP ME PLZ!!!!! Plz!!!
Charra [1.4K]

Answer:

hi the right answer is option C.112

here's why:

\frac{14}{50}  \times 400 = 112

4 0
2 years ago
Karina is designing a logo on a coordinate plane. The logo is a square whose area is 200 square units. She places a circle in th
Katarina [22]

Answer:

D

Step-by-step explanation:

To find the percentage we must first find the area of the circle:

We can find the radius of the circle using the distance formula;

⇒ d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}

⇒ r = \sqrt{(6.3 - 0)^{2} + (1.6 - 0)^{2}}

⇒ r = 6.5

Now we calculate the area;

⇒ A = \pi r^{2}

⇒ A = \pi (6.5)^{2}

⇒ A = \frac{169}{4}\pi

To get the percentage we divide the area of the circle by the square’s are and multiply by 100;

⇒ Percentage = \frac{42.25\pi }{200} * 100

⇒ Percentage = 66 (2sf)

5 0
2 years ago
Write and equation for the shift of the parent graph y=1/x
SashulF [63]
You can think of this equation as \bf f(x)=\cfrac{1}{x}\implies f(x)=(x)^{-1}

and thus apply the transformations to it as such

\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

1)  D = 2, C = +3

2) D = -12, C = -2

3) C = +6, D = 3

4) C = -7, D = -7
7 0
2 years ago
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