Answer:
The probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.
Step-by-step explanation:
Represent the provided data as follows:
Compute the probability of the number of Protestants that were calm for 2 out of 3 days as follows:
The number of Protestants surveyed is, <em>n</em> (Protestants) = 99.
The number of Protestants who were calm for 2 days,
<em>n</em> (Protestants who were calm for 2 days) = 6
The required probability is:
Thus, the probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.
Answer:
8 units
Step-by-step explanation:
because they have the same y axis all we need to do is subtract the distance between the x axis to get the distance between the points
Answer:
C −2a^3+9a^2+45a+6ab^2+18b^2
Step-by-step explanation:
(a+3) ( −2a^2+15a+6b^2)
Distribute the a to the large term in parentheses and the 3 to the large term in parentheses
a ( −2a^2+15a+6b^2)+3 ( −2a^2+15a+6b^2)
−2a^3+15a^2+6ab^2 −6a^2+45a+18b^2
Combine like terms
−2a^3+15a^2−6a^2+6ab^2 +45a+18b^2
-2 a^3 + 9 a^2 + 6 a b^2 + 45 a + 18 b^2
Answer:
Therefore, the probability is P=0.74.
Step-by-step explanation:
We know that Jose estimates that if he leaves his car parked outside his office all day on a weekday, the chance that he will get a parking ticket is 26%.
Therefore the probability that he will get a parking ticket is P1=0.26.
We calculate the probability that he will not get a parking ticket.
We get:
P=1-P1
P=1-0.26
P=0.74
Therefore, the probability is P=0.74.
There is not sufficient evidence to support the claim that over 40% of the public recognize its brand name and associate it with computer equipment thus the company should not continue to advertise during the Super Bowls. So No. Hope I helped have a good day !
