Answer:
hi hi hi hi hi
Step-by-step explanation:
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I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.
A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.
Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.
The number of ways of drawing 2 aces and 3 2s is

and the number of ways of drawing 3 aces and 2 2s is the same,

so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.
Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is

The total number of hands that can be drawn is

Then the probability of getting a full house is

Answer:
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Step-by-step explanation:
If we plot -1.5 and -1.76, we would see thant -1.5 is to the right of -1.76
Right means larger here, so -1.5 is larger
Answer:
the answer would be no solution
Step-by-step explanation:
because, Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation
3/4y-(5/x)=0
and from there you may not do anything else.
Answer:
85 pens
Step-by-step explanation:
The computation of the number of green pens sold is shown below;
As the number of black pens, red pens, and green pans is 3:5:6
And, the ratio of sold of black pens, red pens, and green pans is 7:3:4
So, the ratio of pens in a number of pens is
= 3 × 7 : 5 × 3 : 4 × 6
= 21: 15 : 24
= 7: 5 : 8
And, the total of 212 pens are sold
So, the number of green pens sold is
= 8 × 212 ÷ (7 + 5 + 8)
= 85 pens