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maria [59]
2 years ago
9

Answer as soon as possible

Mathematics
2 answers:
Ipatiy [6.2K]2 years ago
8 0

Answer:

C. -2a^3+9a^2+45a+6ab^2+18b^2

Step-by-step explanation:

Product of (a+3) and (-2a^2+15a+6b^2)

(a+3)(-2a^2+15a+6b^2)

By distributive property,

a(-2a^2+15a+6b^2)+3(-2a^2+15a+6b^2)

Again by distributive property,

-2a^3+15a^2+6ab^2-6a^2+45a+18b^2

Combine like terms,

-2a^3+9a^2+45a+6ab^2+18b^2

Hence, Option 'C' is correct.

alexandr1967 [171]2 years ago
3 0

Answer:

C −2a^3+9a^2+45a+6ab^2+18b^2

Step-by-step explanation:

(a+3) ( −2a^2+15a+6b^2)

Distribute the a to the large term in parentheses and the 3 to the large term in parentheses

a ( −2a^2+15a+6b^2)+3  ( −2a^2+15a+6b^2)

−2a^3+15a^2+6ab^2 −6a^2+45a+18b^2

Combine like terms

−2a^3+15a^2−6a^2+6ab^2 +45a+18b^2

-2 a^3 + 9 a^2 + 6 a b^2 + 45 a + 18 b^2

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Set D is the set of positive two-digit even numbers less than 25 that do not contain the digit 0.
gavmur [86]

The required set of positive two-digit even numbers less than 25 that do not contain the digit 0 is 12,14,16,18,22,24.

<h3>What is integer?</h3>

An integer is a whole number (not a fractional number) that can be positive, negative, or zero. Zero is not a fraction or decimal of any number. It is neither positive nor negative.

Given:

Set D is the set of positive two-digit even numbers less than 25 that do not contain the digit 0.

According to given question we have

2-digit numbers are the numbers that have two digits and they start from the number 10 and end on the number 99.

Starting at 12 going up the two digit numbers even numbers less than 25 that do not contain the digit 0.

12,14,16,18,22,24

Therefore, the required set of positive two-digit even numbers less than 25 that do not contain the digit 0 is 12,14,16,18,22,24.

Learn more details about integer here:

brainly.com/question/15276410

#SPJ1

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