<span>All of the following are examples of composite numbers except which one?
2.</span>
The first equation is 
(Equation 1)
The second equation is 
(Equation 2)
Putting the value of x from equation 1 in equation 2.
we get,
by simplifying the given equation,
Using discriminant formula,
Now the formula for solution 'x' of quadratic equation is given by:
Hence, these are the required solutions.
Answer:
n ≥ 1/5
Step-by-step explanation:
Let the number be n. Then 5n + 2 ≥ 3.
If you want to solve this for n, then subtract 2 from both sides, obtaining:
5n ≥ 1. Isolate n by dividing both sides by 5. Then we have n ≥ 1/5
Answer:
Step-by-step explanation:
Answer:
x = -1, y = 1
Step-by-step explanation:
6 + 4x - 2y = 0 (1)
-3 - 7y = 10x (2)
From (1)
6 + 4x - 2y = 0 (1)
4x - 2y = -6 (3)
From (2)
-3 - 7y = 10x (2)
10x + 7y = -3 (4)
4x - 2y = -6 (3)
10x + 7y = -3 (4)
Using elimination method
Multiply (3) by 10 and (4) by 4 to eliminate x
40x - 20y = -60
40x + 28y = -12
28y - (-20y) = -12 - (-60)
28y + 20y = -12 + 60
48y = 48
y = 48/48
y = 1
Substitute y = 1 into (3)
4x - 2y = -6 (3)
4x - 2(1) = -6
4x - 2 = -6
4x = -6 + 2
4x = -4
x = -4/4
x = -1
x = -1, y = 1
The value of x in the equation is -1
