Usually it’s either 5400 or 7200RPM
Answer:
cout << setprecision(2)<< fixed << number;
Explanation:
The above statement returns 12.35 as output
Though, the statement can be split to multiple statements; but the question requires the use of a cout statement.
The statement starts by setting precision to 2 using setprecision(2)
This is immediately followed by the fixed manipulator;
The essence of the fixed manipulator is to ensure that the number returns 2 digits after the decimal point;
Using only setprecision(2) in the cout statement will on return the 2 digits (12) before the decimal point.
The fixed manipulator is then followed by the variable to be printed.
See code snippet below
<em>#include <iostream> </em>
<em>#include <iomanip>
</em>
<em>using namespace std; </em>
<em>int main() </em>
<em>{ </em>
<em> // Initializing the double value</em>
<em> double number = 12.3456; </em>
<em> //Print result</em>
<em> cout << setprecision(2)<< fixed << number; </em>
<em> return 0; </em>
<em>} </em>
<em />
The answer is B.
<span> desktop publishing program must be able to take text and graphics from a number of sources and allow these elements to be arranged on a page.
The main purpose of a destkop publishing program is to aid user in creating documents using its page layout so it could generate printable media with higher quality compared to the one that is handmade.</span>
Answer:
from socket import *
hostname = input('Enter the host to be scanned: ')
ip_add = gethostbyname(hostname)
connections = [ ]
for i in range(133, 136):
s = socket(AF_INET, SOCK_STREAM)
conn = s.connect_ex((ip_add, i))
print(conn)
connections.append(conn)
if 0 in connections:
print ('Host is online')
s.close()
else:
print ('system is unreachable')
Explanation:
The python source code above scans for all the available range of ports in the provided hostname, if any port is available, the host is online else the program print the error message "system is unreachable.
