Ask question

Ask question

All categories

2 years ago

12

Solve for U 11=8+u/7.68

1 answer:

BlackZzzverrR [31]2 years ago

7 0

$\begin{gathered}\\ \sf\longmapsto 11=\frac{8+u}{7.68}\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 11 = \frac{8 + u}{ \frac{192}{25} } \end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 11=\frac{(8+u)×25}{192}\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 11=\frac{200+25u}{192}\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 2112=200+25u\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 2112-25u=200\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -25u=200-2112\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -25u=-1912\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto u=\frac{1912}{25}\end{gathered}$

<u>Alternate form:</u>

<u>u</u><u>=</u><u>76.48</u>

You might be interested in

Something x something x something =70

nadya68 [22]

Here is what the answer to your question is:
7x10x1=70

5 0

2 years ago

Read 2 more answers

Another name for a farmer could be

notka56 [123]

George I believe I think

4 0

2 years ago

Y – 11 = 3(x – 2) <br> in standard form

emmainna [20.7K]

Answer:

3x + y = -5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Distributive Property
Equality Properties

<u>Algebra I</u>

Standard Form: Ax + By = C

Point-Slope Form: y - y₁ = m(x - x₁)

x₁ - x coordinate
y₁ - y coordinate
m - slope

Step-by-step explanation:

<u>Step 1: Define</u>

[PS] y - 11 = 3(x - 2)

<u>Step 2: Rewrite</u>

<em>Find Standard Form</em>

Distribute 3: y - 11 = 3x - 6
Subtract 3x on both sides: -3x - y - 11 = -6
Add 11 to both sides: -3x - y = 5
Factor -1: -1(3x + y) = 5
Divide -1 on both sides: 3x + y = -5

4 0

2 years ago

Joseph typed a 1200- word essay in 25 minutes.at this rate,determine how many words he can type in 45 minutes.

Deffense [45]

First you divide 1200 by 25 (1200/25) it comes out to 48.
That means the he types at a rate of 48wpm. So then all you have to do is multiply 48 and 45 and you get 2160 words.

4 0

2 years ago

Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

6 0

2 years ago