Answer:
1/8
Step-by-step explanation:
This is actually pretty easy.
First, you have the sample of the children.
You know that the family with 3 children, can only have the following children:
MMM: all males
MMF: 2 males, 1 female
MFF: 1 male, 2 females
MFM: 2 males, 1 female (different order)
FMM: 1 female, 2 males
FFM: 2 females, 1 male
FMF: 2 females, 1 male
FFF: 3 females
If you count all of these possibilities, we have 8 possible cases of family with the childrens.
In only one of them, we have only females and no males, which is the last one, all 3 females.
Therefore, the probability to select a family with no male, is only 1/8.
Hello,
Your answer would be: 55
<u><em>My work:</em></u>
For this problem all you have to do is keeping subtracting 3 until you get a matching number in which I got 55.
Hope this helps!
Brainliest!?!
Have a great day:)
~Rendorforestmusic
Given:
Starting point = (0,0)
First ride = (0,4)
Second ride = (3,0)
In map, each unit = 100 ft
To find:
The actual distance between first and second ride.
Solution:
Distance formula: Distance between two points is
Using the distance formula, we get the distance between first ride and second ride in the map is
So, the distance between first ride and second ride in the map is 5 units.
We have,
1 units = 100 ft
5 units = 500 ft
The actual distance between first and second ride is 500 ft.
Therefore, the correct option is C.
<span>1. m∠1 + m∠5 = 180° and m∠1 + m∠4=180°
Given
2. m∠1 + m∠5 = m∠1 + m∠4
Substitution
3. m∠5 = m∠4
</span>Subtraction property of equality
<span>
4. Ray YZ is parallel to Ray UV
</span>If alternate interior angles equal, then lines are ||. <span>
</span>
15 and 1/25 is the mixed number for 15.04
